제출 #953402

#제출 시각아이디문제언어결과실행 시간메모리
953402efishel경주 (Race) (IOI11_race)C++17
100 / 100
318 ms57868 KiB
#include <bits/stdc++.h> // #include "race.h" #define endl '\n' #define mp make_pair #define pb push_back #define f first #define s second #define fo(i,n) for(auto i =0 ; i < n;i++) #define fore(i,l,r) for(auto i = l; i < r;i++) #define forex(i,r,l) for(auto i = r; i >= l; i--) #define ffo(i,n) forex(i,n-1,0) #define all(x) x.begin(),x.end() #define lsb(x) x&(-x) #define sz(x) (int)x.size() #define gcd(a,b) __gcd(a,b) #define vii vector<ii> using namespace std; using ii = pair<int,int>; using ll = long long; using ull = unsigned long long; using vi = vector<ll>; void valid(int in){cout<<((in)?"YES\n":"NO\n");return;} const int N = 1e6 + 7; vector<ii> graph[N]; bool vis[N];int ans = 1e9, sz[N], mn[N],k; void find_sz(int nodo ,int p = -1){sz[nodo]=1; for(auto [v, cost] : graph[nodo]){if(v==p || vis[v])continue; find_sz(v,nodo); sz[nodo] += sz[v]; } } int find_cent(int nodo, int raiz, int p = -1){ for(auto [v,cost] : graph[nodo]){if(v==p || vis[v])continue; if(sz[v]>sz[raiz]/2)return find_cent(v, raiz, nodo); }return nodo; } void dfs_calc(int nodo, int sum = 0,int nivel = 0, int p = -1){ if(sum>k)return; ans = min(ans, mn[k-sum]+ nivel); for(auto [v,cost] : graph[nodo]){if(v==p || vis[v])continue; dfs_calc(v, sum + cost, nivel+1, nodo); } } void dfs_add(int nodo, int sum = 0, int nivel = 0, int p = -1){ if(sum>k)return; mn[sum] = min(mn[sum],nivel); for(auto [v,cost] : graph[nodo]){if(v==p || vis[v])continue; dfs_add(v, sum+cost, nivel+1, nodo); } } void dfs_del(int nodo, int sum = 0, int nivel = 0, int p = -1){ if(sum>k)return; mn[sum] =1e9; for(auto [v,cost] : graph[nodo]){if(v==p || vis[v])continue; dfs_del(v, sum+cost, nivel+1, nodo); } } void solve(int nodo){ find_sz(nodo);int cen = find_cent(nodo,nodo);mn[0]=0; // fo(i,k+2) cout << mn[i] << " "; cout << endl; vis[cen]=1; for(auto [v,cost] : graph[cen]){ if (vis[v]) continue; dfs_calc(v, cost, 1,cen); dfs_add(v,cost, 1,cen); } dfs_del(cen); for(auto [v,cost] : graph[cen]) if (!vis[v]) solve(v); } int best_path(int n, int K, int H[][2], int L[]){k=K;fill(mn, mn+k+3, 1e9); fo(i,n-1){ graph[H[i][0]].pb({H[i][1], L[i]}); graph[H[i][1]].pb({H[i][0], L[i]}); }solve(0);return (ans == 1e9 ? -1 : ans); }
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