이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*
* ___
* _ / _\_
* / | |___|
* | | |
* \_| __ |
* \_/ \_/
* uwu amogus
*/
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define inf 0x7FFFFFFF
#define llinf 0x7FFFFFFFFFFFFFFF
#define ff first
#define ss second
#define FOR(i, a, b) for(int i = a; i < b; i++)
#define ROF(i, a, b) for(int i = a - 1; i >= b; i--)
//#define assert void
//#pragma GCC optimize("O3")
//#pragma GCC optimize("unroll-loops")
//#define int ll
struct dsu {
dsu(int n) {
p.resize(n, -1);
pp.resize(n); for (int i = 0; i < n; i++) pp[i] = i;
r.resize(n, 0);
}
inline int par(int x) {
return pp[_par(x)];
}
inline int _par(int x) {
return p[x] == -1 ? x : p[x] = _par(p[x]);
}
inline void merge(int a, int b) {
a = _par(a); b = _par(b);
if (a == b)return;
if (r[a] < r[b]) {
swap(a, b);
swap(pp[a], pp[b]);
}
if (r[a] == r[b]) r[a]++;
p[b] = a;
}
vector<int> p, r, pp;
};
signed main() {
ios_base::sync_with_stdio(false); cin.tie(NULL);
int N, D, T; cin >> N >> D >> T;
vector<int> t(N); for (auto& x : t) cin >> x;
int l = 0, r = 2e6, m = 0;
int ans = 0;
while (l < r) {//aliens HAHAHAhaha ha ha :sob:
m = (l + r) / 2;
vector<pair<int,int>> st; st.reserve(N);
struct node {
int p = -1;//prev
int n = -1;//next
int lz = 0;
double v = 0;
int c = 0; // count owo!!!
node() {};
node(double v, int c) : v(v), c(c) {};
};
vector<node> st2; st2.reserve(N);
dsu pls(N);
int start = 0;
int amt = 0;//amount added
function<void(int)> kill = [&](int i) {
int n = st2[i].n;
//assert(n != -1);
if (n == -1) return;
if ((st2[i].v + (double)st2[i].lz > st2[n].v)) {
int p = st2[i].p;
st2[n].p = p;
if (p != -1) {
st2[p].lz += st2[i].lz;
st2[p].n = n;
pls.merge(p, i); //merge i to p
kill(p);
}
else {
// DEAD
amt -= st2[i].lz; //recycle owo
start = n;
}
}
};
for (int i = 0; i < N; i++) {
//create and then upd
if (st2.size()) {
st2.push_back(node(st2[start].v + (double)amt + m, st2[start].c+1));
st2[i - 1].n = i; st2[i].p = i - 1;
kill(i - 1);
}
else {
st2.push_back(node());
}
int o = i;
if (t[i] <= T) {
while (st.size() && st.back().ff >= t[i] - i) {
st.pop_back();
}
st.push_back({ t[i] - i, i});
}
else {
while (st.size() && st.back().ff > T - i) st.pop_back();
if (st.size()) {
o = st.back().ss;
}
else o = -1;
}
//cout << o << ",";
if(o >= start){
int t = pls.par(o);
st2[t].lz++; amt++;
kill(t);
}
//cout << amt << ",";
}
//cout << endl;
int c = st2[start].c;
//cout << c << endl;
if (c <= D) {
r = m - 1;
ans = round((double)st2[start].v + (double)amt - (double)D * m);
}
else {
//cout << "fuck" << endl;
l = m + 1;
}
}
cout << ans << endl;
// n log n inverse ackermann n please pass i swear to god
}
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