제출 #952898

#제출 시각아이디문제언어결과실행 시간메모리
952898SirCovidThe19thThe short shank; Redemption (BOI21_prison)C++17
0 / 100
2052 ms348 KiB
/* * ___ * _ / _\_ * / | |___| * | | | * \_| __ | * \_/ \_/ * uwu amogus */ #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") #include <bits/stdc++.h> using namespace std; #define ll long long #define inf 0x7FFFFFFF #define llinf 0x7FFFFFFFFFFFFFFF #define ff first #define ss second #define FOR(i, a, b) for(int i = a; i < b; i++) #define ROF(i, a, b) for(int i = a - 1; i >= b; i--) //#define assert void //#pragma GCC optimize("O3") //#pragma GCC optimize("unroll-loops") //#define int ll struct dsu { dsu(int n) { p.resize(n, -1); pp.resize(n); for (int i = 0; i < n; i++) pp[i] = i; r.resize(n, 0); } inline int par(int x) { return pp[_par(x)]; } inline int _par(int x) { return p[x] == -1 ? x : p[x] = _par(p[x]); } inline void merge(int a, int b) { a = _par(a); b = _par(b); if (a == b)return; if (r[a] < r[b]) { swap(a, b); swap(pp[a], pp[b]); } if (r[a] == r[b]) r[a]++; p[b] = a; } vector<int> p, r, pp; }; signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int N, D, T; cin >> N >> D >> T; vector<int> t(N); for (auto& x : t) cin >> x; int l = 0, r = 2e6, m = 0; int ans = 0; while (l < r) {//aliens HAHAHAhaha ha ha :sob: m = (l + r) / 2; vector<pair<int,int>> st; struct node { int p = -1;//prev int n = -1;//next int lz = 0; double v = 0; int c = 0; // count owo!!! node() {}; node(double v, int c) : v(v), c(c) {}; }; vector<node> st2; dsu pls(N); int start = 0; int amt = 0;//amount added function<void(int)> kill = [&](int i) { int n = st2[i].n; //assert(n != -1); if (n == -1) return; if ((st2[i].v + (double)st2[i].lz > st2[n].v)) { int p = st2[i].p; st2[n].p = p; if (p != -1) { st2[p].lz += st2[i].lz; st2[p].n = n; pls.merge(p, i); //merge i to p kill(p); } else { // DEAD amt -= st2[i].lz; //recycle owo start = n; } } }; for (int i = 0; i < N; i++) { //create and then upd if (st2.size()) { st2.push_back(node(st2[start].v + (double)amt + m, st2[start].c+1)); st2[i - 1].n = i; st2[i].p = i - 1; kill(i - 1); } else { st2.push_back(node()); } int o = i; if (t[i] <= T) { while (st.size() && st.back().ff >= t[i] - i) { st.pop_back(); } st.push_back({ t[i] - i, i}); } else { while (st.size() && st.back().ff > T - i) st.pop_back(); if (st.size()) { o = st.back().ss; } else o = -1; } //cout << o << ","; if(o >= start){ int t = pls.par(o); st2[t].lz++; amt++; kill(t); } //cout << amt << ","; } //cout << endl; int c = st2[start].c; //cout << c << endl; if (c <= D) { r = m - 1; ans = round((double)st2[start].v + (double)amt - (double)D * m); } else { //cout << "fuck" << endl; l = m; } } cout << ans << endl; // n log n inverse ackermann n please pass i swear to god }
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