이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int MAX_N = 1e5;
const int MAX_M = 2e5;
const int MAX_K = 5;
const long long INF = 1e15;
struct edge {
int u, v, c;
int other( int x ) {
return u ^ v ^ x;
}
};
struct dv {
int v;
long long d;
bool operator < ( const dv &x ) const {
return d > x.d;
}
};
int cities[MAX_K];
vector<vector<int>> perms;
vector<int> adj[MAX_N + 1];
edge edges[MAX_M];
bool vis[MAX_N + 1];
long long dist[MAX_K][MAX_N + 1];
int parent[MAX_K][MAX_N + 1];
void dijkstra( int s, long long dist[], int parent[] ) {
priority_queue<dv> pq;
for ( int v = 0; v <= MAX_N; v++ )
dist[v] = INF;
dist[s] = 0;
parent[s] = 0;
pq.push( { s, dist[s] } );
while ( !pq.empty() ) {
int u = pq.top().v;
int d = pq.top().d;
pq.pop();
if ( d > dist[u] )
continue;
for ( int e: adj[u] ) {
int v = edges[e].other( u );
if ( dist[u] + edges[e].c < dist[v] ) {
dist[v] = dist[u] + edges[e].c;
parent[v] = u;
pq.push( { v, dist[v] } );
}
}
}
}
int main() {
int n, k, m;
cin >> n >> k >> m;
//genperm( 0, k );
for ( int i = 0; i < k; i++ )
cin >> cities[i];
for ( int i = 0; i < m; i++ ) {
cin >> edges[i].u >> edges[i].v >> edges[i].c;
adj[edges[i].u].push_back( i );
adj[edges[i].v].push_back( i );
}
for ( int i = 0; i < k; i++ )
dijkstra( cities[i], dist[i], parent[i] );
long long d = 0;
vis[cities[0]] = true;
for ( int i = 1; i < k; i++ ) {
int u = 0;
for ( int v = 1; v <= n; v++ ) {
if ( vis[v] && dist[i][v] < dist[i][u] )
u = v;
}
d += dist[i][u];
int c = cities[i];
while ( u != c ) {
u = parent[i][u];
vis[u] = true;
}
}
cout << d;
return 0;
}
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