제출 #951056

#제출 시각아이디문제언어결과실행 시간메모리
951056Gromp15Two Antennas (JOI19_antennas)C++17
100 / 100
632 ms40132 KiB
#include <bits/stdc++.h> #define ll long long #define ar array #define db double #define all(x) x.begin(), x.end() #define sz(x) (int)x.size() using namespace std; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); #define rint(l, r) uniform_int_distribution<int>(l, r)(rng) template<typename T> bool ckmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; } template<typename T> bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; } const int INF = int(1e9) + 5; struct seg { int N; vector<int> tree, tree2, lazy; seg(int n) : N(1<<(__lg(n)+1)), tree(2*N, -1), tree2(2*N, 1e9), lazy(2*N, -INF) {} void push(int node) { if (lazy[node] == -INF) return; ckmax(tree[node], lazy[node] - tree2[node]); if (node < N) { ckmax(lazy[node*2], lazy[node]); ckmax(lazy[node*2+1], lazy[node]); } lazy[node] = -INF; } void update(int node, int nl, int nr, int pos, int x) { push(node); if (pos > nr || pos < nl) return; if (nl == nr && nl == pos) { tree2[node] = x; return; } int mid = (nl+nr)/2; update(node*2, nl, mid, pos, x); update(node*2+1, mid+1, nr, pos, x); tree[node] = max(tree[node*2], tree[node*2+1]); tree2[node] = min(tree2[node*2], tree2[node*2+1]); } void update2(int node, int nl, int nr, int ql, int qr, int x) { push(node); if (ql > nr || qr < nl) return; if (ql <= nl && nr <= qr) { ckmax(lazy[node], x); push(node); return; } int mid = (nl+nr)/2; update2(node*2, nl, mid, ql, qr, x); update2(node*2+1, mid+1, nr, ql, qr, x); tree[node] = max(tree[node*2], tree[node*2+1]); } int query(int node, int nl, int nr, int ql, int qr) { push(node); if (ql > nr || qr < nl) return -1; if (ql <= nl && nr <= qr) { return tree[node]; } int mid = (nl+nr)/2; return max(query(node*2, nl, mid, ql, qr), query(node*2+1, mid+1, nr, ql, qr)); } void update(int pos, int x) { update(1, 0, N-1, pos, x); } void update2(int l, int r, int x) { update2(1, 0, N-1, l, r, x); } int query(int l, int r) { return query(1, 0, N-1, l, r); } }; void test_case() { int n; cin >> n; vector<int> h(n), a(n), b(n); for (int i = 0; i < n; i++) cin >> h[i] >> a[i] >> b[i]; int q; cin >> q; vector<int> ans(q, -1); vector<vector<ar<int, 2>>> queries(n); for (int i = 0; i < q; i++) { int l, r; cin >> l >> r; l--, r--; queries[r].push_back({l, i}); } for (int t = 0; t < 2; t++) { seg st(n); vector<vector<int>> in(n), out(n); for (int i = 0; i < n; i++) { if (i + a[i] < n) in[i + a[i]].emplace_back(i); if (i + b[i] + 1 < n) out[i + b[i] + 1].emplace_back(i); } for (int i = 0; i < n; i++) { for (int p : in[i]) st.update(p, h[p]); for (int p : out[i]) st.update(p, 1e9); int l = max(0, i - b[i]), r = i - a[i]; if (l <= r) { st.update2(l, r, h[i]); } for (auto [from, ans_idx] : queries[i]) { ckmax(ans[ans_idx], st.query(from, i)); } } for (int &x : h) x *= -1; } for (int i = 0; i < q; i++) cout << ans[i] << '\n'; } int main() { cin.tie(0)->sync_with_stdio(0); int t = 1; // cin >> t; while (t--) test_case(); }
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