#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define int long long
#define rnd(l, r) uniform_int_distribution<int>(l, r)(rng)
using namespace std;
void fp(string name){freopen((name+".in").c_str(),"r",stdin); freopen((name+".out").c_str(),"w",stdout);}
int pow(int a,int b,int m){int ans=1;while(b){if(b&1){ans=(ans*a)%m;}b>>=1;a=(a*a)%m;}return ans;}
int binpow(int a,int b){int ans=1;while(b){if(b&1){ans=(ans*a);}b>>=1;a=(a*a);}return ans;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int N = 2e5 + 10, MX = 2e5 + 10, inf = 1e18;
int a[N], dp[N], t[N * 4];
void update(int pos, int x, int v = 1,int tl = 0, int tr = MX){
if(tl == tr){
t[v] += x;
}else{
int mid = (tl + tr) >> 1;
if(pos <= mid)
update(pos, x, v * 2, tl, mid);
else
update(pos, x, v * 2 + 1,mid + 1, tr);
t[v] = (t[v * 2] + t[v * 2 + 1]);
}
}
int get(int l, int r, int v = 1, int tl = 0, int tr = MX){
if(tl > r || tr < l)
return 0;
if(tl >= l && tr <= r){
return t[v];
}
int mid = (tl + tr) >> 1;
return (get(l, r, v * 2, tl, mid) + get(l, r, v * 2 + 1, mid + 1, tr));
}
main(){
iostream::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
int n, q;
cin >> n >> q;
for(int i = 1; i <= n; i++){
cin >> a[i];
}
while(q--){
int l, r, x;
cin >> l >> r >> x;
for(int i = l; i <= r; i++){
a[i] += x;
}
for(int i = 1; i <= n; i++){
int mx = -inf, mn = inf;
for(int j = i; j >= 1; j--){
mx = max(a[j], mx);
mn = min(mn, a[j]);
dp[i] = max(dp[j - 1] + mx - mn, dp[i]);
}
}
cout << dp[n] << endl;
for(int i = 1; i <= n; i++){
dp[i] = -inf;
}
//cout << endl;
}
//cout << ans << endl;
}
/*
* Before implementing the problem:
Do I understand the problem correctly?
Which places are tricky? What do I need to remember to implement them correctly?
Which place is the heaviest by implementation? Can I do it simpler?
Which place is the slowest? Where do I need to be careful about constant factors and where I can choose slower but simpler implementation?
----------------------------------
If not AC:
Did you remember to do everything to handle the tricky places you thought about before?
Is the solution correct?
Do I understand the problem correctly?
----------------------------------
If you have a test on which the solution gives wrong answer:
Is the solution doing what it was supposed to do?
Is the problem in the code or in the idea?
*/
Compilation message
Main.cpp:47:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
47 | main(){
| ^~~~
Main.cpp: In function 'void fp(std::string)':
Main.cpp:15:29: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
15 | void fp(string name){freopen((name+".in").c_str(),"r",stdin); freopen((name+".out").c_str(),"w",stdout);}
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:15:70: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
15 | void fp(string name){freopen((name+".in").c_str(),"r",stdin); freopen((name+".out").c_str(),"w",stdout);}
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
7 ms |
2396 KB |
Output is correct |
2 |
Correct |
7 ms |
2396 KB |
Output is correct |
3 |
Correct |
7 ms |
2396 KB |
Output is correct |
4 |
Correct |
7 ms |
2396 KB |
Output is correct |
5 |
Correct |
7 ms |
2396 KB |
Output is correct |
6 |
Correct |
7 ms |
2396 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
7 ms |
2396 KB |
Output is correct |
2 |
Correct |
7 ms |
2396 KB |
Output is correct |
3 |
Correct |
7 ms |
2396 KB |
Output is correct |
4 |
Correct |
7 ms |
2396 KB |
Output is correct |
5 |
Correct |
7 ms |
2396 KB |
Output is correct |
6 |
Correct |
7 ms |
2396 KB |
Output is correct |
7 |
Execution timed out |
2017 ms |
2544 KB |
Time limit exceeded |
8 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
7 ms |
2396 KB |
Output is correct |
2 |
Correct |
7 ms |
2396 KB |
Output is correct |
3 |
Correct |
7 ms |
2396 KB |
Output is correct |
4 |
Correct |
7 ms |
2396 KB |
Output is correct |
5 |
Correct |
7 ms |
2396 KB |
Output is correct |
6 |
Correct |
7 ms |
2396 KB |
Output is correct |
7 |
Execution timed out |
2017 ms |
2544 KB |
Time limit exceeded |
8 |
Halted |
0 ms |
0 KB |
- |