제출 #950029

#제출 시각아이디문제언어결과실행 시간메모리
950029hotboy2703Copy and Paste 3 (JOI22_copypaste3)C++14
15 / 100
3098 ms64660 KiB
#include<bits/stdc++.h>
using ll = long long;
using namespace std;
#define pll pair <ll,ll>
#define fi first
#define se second
#define sz(a) (ll((a).size()))
#define BIT(mask,i) (((mask) >> (i))&1)
#define MASK(i) (1LL << (i))
#define MP make_pair
ll t;
string s;
ll a,b,c;
ll n;
ll dp[2510][2510];
ll type[2510][2510];
int main(){
    ios_base::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr);
    cin>>t;
//    while (t--){
        cin>>s;
        cin>>a>>b>>c;
        n = sz(s);
        s = "x" + s;
        for (ll k = 1;k <= n;k ++){
            ll ptr = 1;
            for (ll l = 1,r = k; r <= n; l++,r++){
                for (ll l1 = 1,r1 = k; l1 < l; l1++,r1++){
                    bool ok = 1;
                    for (ll j = 0;j < k;j ++){
                        if (s[j+l1] != s[j+l])ok = 0;
                    }
                    if (ok){type[k][l] = type[k][l1];break;}
                }
                if (type[k][l] == 0)type[k][l] = ptr++;
//                cout<<type[k][l]<<' ';
            }
//            cout<<'\n';
        }
        for (ll k = 1;k <= n;k ++){
            for (ll l = 1,r = k; r <= n; l++,r++){
                dp[l][r] = (r-l+1)*a;
                for (ll l1 = l;l1 <= r;l1 ++){
                    for (ll r1 = l1;r1 <= r;r1 ++){
                        ll sz = r1-l1+1;
                        ll sum = dp[l1][r1] + b;
                        for (ll j = l;j <= r;j ++){
                            if (j + sz - 1 <= r && type[sz][j] == type[sz][l1]){
                                sum += c;
                                j+=sz-1;
                            }
                            else{
                                sum += a;
//                                j++;
                            }
                        }
                        dp[l][r] = min(dp[l][r],sum);
                    }
                }
            }
        }
//        cout<<dp[3][5]<<'\n';
        cout<<dp[1][n]<<'\n';
//    }
}
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