답안 #949973

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
949973 2024-03-20T02:08:44 Z vjudge1 Printed Circuit Board (CEOI12_circuit) C++17
100 / 100
35 ms 2908 KB
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <cassert>
#include <vector>
typedef long long ll;
//typedef double ld;
const ll INF = 1e17;
const int LEN = 2e5 + 1;
int N;
bool V[LEN];

struct Pos {
	int x, y, i;
	Pos(int X = 0, int Y = 0, int I = 0) : x(X), y(Y), i(I) {}
	bool operator == (const Pos& p) const { return x == p.x && y == p.y; }
	bool operator != (const Pos& p) const { return x != p.x || y != p.y; }
	ll operator * (const Pos& p) const { return { (ll)x * p.x + (ll)y * p.y }; }
	ll operator / (const Pos& p) const { return { (ll)x * p.y - (ll)y * p.x }; }
	bool operator < (const Pos& p) const { return *this / p > 0; }
	bool operator <= (const Pos& p) const { return *this / p >= 0; }
	Pos operator + (const Pos& p) const { return { x + p.x, y + p.y }; }
	Pos operator - (const Pos& p) const { return { x - p.x, y - p.y }; }
	ll Euc() const { return (ll)x * x + (ll)y * y; }
	friend std::istream& operator >> (std::istream& is, Pos& p) {
		is >> p.x >> p.y;
		return is;
	}
	friend std::ostream& operator << (std::ostream& os, const Pos& p) {
		os << p.x << " " << p.y;
		return os;
	}
}; const Pos O = { 0, 0 };
std::vector<Pos> C, H;
ll cross(const Pos& d1, const Pos& d2, const Pos& d3) { return (d2 - d1) / (d3 - d2); }
int ccw(const Pos& d1, const Pos& d2, const Pos& d3) {
	ll ret = cross(d1, d2, d3);
	return !ret ? 0 : ret > 0 ? 1 : -1;
}
ll area(const std::vector<Pos>& H) {
	ll ret = 0;
	int sz = H.size();
	for (int i = 0; i < sz; i++) {
		Pos cur = H[i], nxt = H[(i + 1) % sz];
		ret += cross(O, cur, nxt);
	}
	return ret;
}
bool norm(std::vector<Pos>& H) {
	if (area(H) > 0) {
		std::reverse(H.begin(), H.end());
		return 1;
	}
	return 0;
}
int invisible(const Pos& p1, const Pos& p2, const Pos& t) {
	if (p1 / t == 0 && p1.Euc() <= t.Euc()) return 1;
	if (p2 / t == 0 && p2.Euc() <= t.Euc()) return 1;
	return ccw(O, p1, t) < 0 && ccw(O, p2, t) > 0 && ccw(p1, p2, t) > 0;
}
std::vector<int> stack;
void solve() {
	std::cin.tie(0)->sync_with_stdio(0);
	std::cout.tie(0);
	memset(V, 0, sizeof V);
	std::cin >> N;
	H.resize(N);
	for (int i = 0; i < N; i++) std::cin >> H[i], H[i].i = i + 1;
	norm(H);//normalization cw

	int r = 0, l = 0;
	ll LMIN = H[0].Euc(), RMIN = H[0].Euc();
	for (int i = 0; i < N; i++) {
		if (H[r] / H[i] < 0 ||
			(H[r] / H[i] == 0 && RMIN > H[i].Euc())) {
			r = i, RMIN = H[i].Euc();
		}
		if (H[l] / H[i] > 0 ||
			(H[l] / H[i] == 0 && LMIN > H[i].Euc())) {
			l = i, LMIN = H[i].Euc();
		}
	}

	stack.clear();
	stack.push_back(r);
	V[H[r].i] = 1;

	bool fvis = 1, bvis = 1, rvs = 0;
	for (int i = r; i < r + N; i++) {
		if (i % N == l) break;
		if (fvis && bvis) {
			int CCW = ccw(H[(i - 1 + N) % N], H[i % N], H[(i + 1) % N]);
			if (H[i % N] / H[(i + 1) % N] < 0) {//move backward
				if (!rvs && CCW < 0) {
					rvs = 1;
					fvis = 0;
					continue;
				}
				rvs = 1;
				while (stack.size() && invisible(H[i % N], H[(i + 1) % N], H[stack.back() % N]))
					stack.pop_back();
			}
			else if (H[i % N] / H[(i + 1) % N] == 0) {//move vertical
				if (H[i % N].Euc() > H[(i + 1) % N].Euc()) {
					//rvs = 0;
					if (stack[stack.size() - 1] == i) stack.pop_back();
					if (stack.size() < 1 || H[stack.back() % N] / H[(i + 1) % N] > 0)
						stack.push_back(i + 1);
				}
			}
			else if (H[i % N] / H[(i + 1) % N] > 0) {//move forward
				if (rvs && CCW > 0) {
					stack.push_back(i);
					rvs = 0;
					bvis = 0;
					continue;
				}
				if (rvs && H[stack.back() % N] / H[i % N] > 0) stack.push_back(i);
				rvs = 0;
				if (stack.size() < 1 || H[stack.back() % N] / H[(i + 1) % N] > 0)
					stack.push_back(i + 1);
			}
		}
		else if (!fvis) {
			if (H[stack.back() % N] / H[(i + 1) % N] > 0) {
				rvs = 0;
				fvis = 1;
				stack.push_back(i + 1);
			}
		}
		else if (!bvis) {
			if (H[stack.back() % N] / H[(i + 1) % N] < 0) {
				stack.pop_back();
				rvs = 1;
				bvis = 1;
				while (stack.size() && invisible(H[i % N], H[(i + 1) % N], H[stack.back() % N]))
					stack.pop_back();
			}
		}
	}
	for (const int& i : stack) V[H[i % N].i] = 1;
	std::cout << stack.size() << "\n";
	for (int i = 1; i <= N; i++) if (V[i]) std::cout << i << " ";
	return;
}
int main() { solve(); return 0; }//boj3303 Printed Circuit Board
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 600 KB Output is correct
2 Correct 1 ms 604 KB Output is correct
3 Correct 1 ms 604 KB Output is correct
4 Correct 1 ms 600 KB Output is correct
5 Correct 2 ms 604 KB Output is correct
6 Correct 2 ms 604 KB Output is correct
7 Correct 4 ms 860 KB Output is correct
8 Correct 2 ms 604 KB Output is correct
9 Correct 2 ms 604 KB Output is correct
10 Correct 2 ms 604 KB Output is correct
11 Correct 2 ms 604 KB Output is correct
12 Correct 3 ms 860 KB Output is correct
13 Correct 5 ms 860 KB Output is correct
14 Correct 6 ms 1116 KB Output is correct
15 Correct 7 ms 1116 KB Output is correct
16 Correct 15 ms 1624 KB Output is correct
17 Correct 15 ms 1628 KB Output is correct
18 Correct 27 ms 2904 KB Output is correct
19 Correct 27 ms 2908 KB Output is correct
20 Correct 35 ms 2908 KB Output is correct