이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
vector<pair<int,long long>>g[1000000];
int currentnode(int i,int j,int column)
{
return i*(column+2)+j+1;
}
vector<long long>shortest_path(int source)
{
vector<long long>answer(1000000,1000000000000000000);
priority_queue<pair<long long,int>,vector<pair<long long,int>>,greater<pair<long long,int>>>pq;
vector<int>used(1000000,0);
pq.push({0,source});
while(pq.size())
{
//cout<<"A"<<endl;
int node=pq.top().second;
long long cost=pq.top().first;
pq.pop();
if(used[node])continue;
used[node]=1;
answer[node]=cost;
for(pair<int,long long>go:g[node])
{
if(used[go.first])continue;
pq.push({go.second+cost,go.first});
}
}
return answer;
}
int main()
{
int n,m;
cin>>m>>n;
for(int i=1;i<=m;i++)
for(int j=1;j<=n;j++)
{
char a;
cin>>a;
//cout<<"currentnode "<<currentnode(i,j,n)<<endl;
if(a=='W')
{
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-1,0});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-n-2,1});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+1,2});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+n+2,3});
}
else if(a=='E')
{
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+1,0});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+n+2,1});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-1,2});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-n-2,3});
}
else if(a=='S')
{
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+n+2,0});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-1,1});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-n-2,2});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+1,3});
}
else if(a=='N')
{
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-n-2,0});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+1,1});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)+n+2,2});
g[currentnode(i,j,n)].push_back({currentnode(i,j,n)-1,3});
}
}
vector<long long>dis=shortest_path(n+4);
//for(int i=1;i<=(n+2)*(m+2);i++)cout<<dis[i]<<" ";cout<<endl;
if(dis[(n+2)*(m+2)-n-3]==1000000000000000000)cout<<-1;
else cout<<dis[(n+2)*(m+2)-n-3];
return 0;
}
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