Submission #946806

#TimeUsernameProblemLanguageResultExecution timeMemory
946806GrindMachineStar Trek (CEOI20_startrek)C++17
23 / 100
1059 ms13168 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; vector<ll> adj[N]; vector<ll> dp1(N), dp2(N), dp3(N); void dfs1(ll u, ll p){ dp1[u] = 0; trav(v,adj[u]){ if(v == p) conts; dfs1(v,u); dp1[u] |= dp1[v]^1; } } void dfs2(ll u, ll p){ if(dp1[u]) return; dp1[u] = 0; trav(v,adj[u]){ if(v == p) conts; dfs2(v,u); dp1[u] |= dp1[v]^1; } } void solve(int test_case) { ll n,d; cin >> n >> d; rep1(i,n-1){ ll u,v; cin >> u >> v; adj[u].pb(v), adj[v].pb(u); } rep1(i,n){ dfs1(i,-1); dp2[i] = dp1[i]; } dfs1(1,-1); auto odp1 = dp1; rep1(i,n){ if(odp1[i]){ dp3[i] = dp2[1]; conts; } rep1(j,n) dp1[j] = 0; dp1[i] = 1; dfs2(1,-1); dp3[i] = dp1[1]; } ll lose_cnt = 0; rep1(i,n) lose_cnt += dp2[i]^1; ll ans = 0; rep1(u,n){ ll ways = 0; if(odp1[u]){ if(dp2[1]){ ways = n; } } else{ if(dp2[1]){ ways = n-lose_cnt; } if(dp3[u]){ ways += lose_cnt; } } ans += ways; } ans %= MOD; cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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