이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*****from dust I have come, dust I will be*****/
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define int long long
#define forn(i,n) for(int i=0;i<n;i++)
int dx[8] = { 1, 0, -1, 0, -1, 1, -1, 1 };
int dy[8] = { 0, 1, 0, -1, -1, 1, 1, -1 };
int ceil_div(int a, int b) {return a % b == 0 ? a / b : a / b + 1;}
const int MOD = 1000000007;
//const int MOD = 998244353;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds; // find_by_order, order_of_key
/*
int k = A.order_of_key(p[i].second);
A.erase(A.find_by_order(k));
erase element from pbds multiset
*/
int bfs(vector<vector<int>>&g, int start, int n){
vector<int>vis(n, 0);
queue<int>q;
q.push(start);
vis[start] = 1;
int cost = 0, cnt = 0;
while (!q.empty()){
auto t = q.front();
q.pop();
for (auto x : g[t]){
if (vis[x] == 0){
cnt++;
vis[x] = vis[t] + 1;
cost += vis[x];
q.push(x);
}
}
}
if (cnt != n-1) return 1e18;
return cost + 1;
}
void solve(){
int n; cin >> n;
vector<vector<int>>g(n);
forn(i,n){
int sz; cin >> sz;
int x;
forn(j,sz){
cin >> x;
g[x-1].push_back(i);
}
}
int ans = 1e18;
forn(i,n){
ans = min(ans, bfs(g,i,n));
}
cout <<ans<<'\n';
}
int32_t main(){
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int t = 1; //cin >>t;
for (int i=1;i<=t;i++){
solve();
}
return 0;
}
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