#define _CRT_SECURE_NO_WARNINGS
#include <bits/stdc++.h>
//#include <ext/pb_ds/tree_policy.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;
#define FOR(i,start,end) for(int i=start;i<(int)(end);i++)
#define FORE(i,start,end) for(int i=start;i<=(int)end;i++)
#define RFOR(i,start,end) for(int i = start; i>end; i--)
#define RFORE(i,start,end) for(int i = start; i>=end; i--)
#define all(a) a.begin(), a.end()
#define mt make_tuple
#define mp make_pair
#define v vector
#define sf scanf
#define pf printf
#define dvar(x) cout << #x << " := " << x << "\n"
#define darr(x,n) FOR(i,0,n) cout << #x << "[" << i << "]" << " := " << x[i] << "\n"
typedef long long ll;
typedef long double ld;
typedef pair<int, int > pii;
typedef pair<ll, ll> pll;
//template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T> void minn(T &a, T b) { a = min(a, b); }
template<class T> void maxx(T &a, T b) { a = max(a, b); }
void io() {
#ifdef LOCAL_PROJECT
freopen("input.in", "r", stdin); freopen("output.out", "w", stdout);
#else
/* online submission */
#endif
ios_base::sync_with_stdio(false); cin.tie(NULL);
}
const ll MOD = 1000000007LL;
const ll PRIME = 105943LL;
const ll INF = 1e18;
/********************CEOI 2017 Day 2 Problem 1******************************/
struct Line {
ll m, b;
Line() {}
Line(ll _m, ll _b) : m(_m), b(_b) {}
inline ll eval(int x) { return m*x + b; }
};
template <int SZ> struct LiChao {
int n;
Line data[SZ * 4];
LiChao() {}
void init(Line def, int N = SZ) {
fill(data, data + N * 4, def);
}
void upd(Line nLine, int ind = 1, int L = 0, int R = SZ - 1) {
int mid = (L + R) / 2;
if (nLine.eval(mid) < data[ind].eval(mid)) swap(nLine, data[ind]);
if (L == R) return;
if (nLine.eval(L) < data[ind].eval(L)) upd(nLine, 2 * ind, L, mid);
else upd(nLine, 2 * ind + 1, mid + 1, R);
}
ll query(int x, int ind = 1, int L = 0, int R = SZ - 1) {
int mid = (L + R) / 2;
ll s = data[ind].eval(x);
if (L < R) {
if (x <= mid) minn(s, query(x, 2 * ind, L, mid));
else minn(s, query(x, 2 * ind + 1, mid + 1, R));
}
return s;
}
};
const int MAXN = 100000;
int N;
ll H[MAXN], W[MAXN];
LiChao<1000001> tree;
int main() {
io();
cin >> N;
FOR(i, 0, N) cin >> H[i];
FOR(i, 0, N) cin >> W[i];
FOR(i, 1, N) W[i] += W[i - 1];
tree.init(Line(-2 * H[0], H[0] * H[0] + 0 - W[0]));
FOR(i, 1, N) {
ll dp = tree.query(H[i]) + W[i - 1] + H[i] * H[i];
if (i == N - 1) {
cout << dp << "\n";
}
tree.upd(Line(-2 * H[i], H[i] * H[i] + dp - W[i]));
}
}
