이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
//#pragma GCC optimize("Ofast,unroll-loops,fast-math,O3")
#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <cassert>
#include <iomanip>
#include <iostream>
#include <algorithm>
#include <stdio.h>
#include <fstream>
#include <unordered_map>
#define ll long long
#define int long long
#define all(v) v.begin(), v.end()
#define nl '\n'
#define pb push_back
#define sz(s) (int)(s).size()
#define f first
#define s second
using namespace std;
const ll N = 2e5 + 50, MX = 5e18;
ll n;
ll a[N], b[N];
ll fst(){
cin >> n;
pair <int, int> p[n+1];
ll lf[n + 1], rf[n + 1];
for(int i = 1; i <= n; i++){
cin >> a[i] >> b[i];
p[i].f = a[i] , p[i].s = b[i];
}
sort(p + 1, p + 1 + n);
ll ans = p[1].s;
ll pr[n+1];
pr[0]=0;
pr[1] = p[1].s;
for(int i = 2; i <= n; i++){
pr[i] = pr[i-1]+p[i].s;
ans = max(ans, p[i].s);
}
for(int i = 1; i <= n; i++){
rf[i] = pr[i] - p[i].f;
lf[i] = p[i].f - pr[i - 1];
}
ll mx = 0;
for(int r = 1; r <= n; r++){
ans = max(ans, rf[r] + mx);
mx = max(lf[r], mx);
}
return ans;
}
void solve(){
cout << fst() << nl;
}
signed main(){
//freopen("lca.in", "r", stdin);
//freopen("lca.out", "w", stdout);
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
ll ql=1;
//cin >> ql;
//tst++;
while(ql--){
solve();
}
}
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