이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
#define fastio ios::sync_with_stdio(false), cin.tie(0);
#pragma GCC optimize("Ofast","unroll-loops")
#define pb push_back
#define eb emplace_back
#define f first
#define s second
#define int long long
#define lowbit(x) x&-x
const int maxn = 3e5 + 5;
const int INF = 1e9 + 7;
int mn[maxn][20], mx[maxn][20];
signed main(void){
fastio;
int n;
cin>>n;
vector<int> a(n);
for(int i = 0; i < n; i++) cin>>a[i];
vector<int> b(n), c(n);
for(int i = 0; i < n; i++){
if(i == n - 1) mx[i][0] = INF;
else mx[i][0] = 2 * a[i + 1] - a[i];
if(!i) mn[i][0] = -INF;
else mn[i][0] = 2 * a[i - 1] - a[i];
}
for(int i = 1; (1 << i) < n; i++){
for(int j = 0; j + (1 << i) - 1 < n; j++){
mx[j][i] = max(mx[j][i - 1], mx[j + (1 << (i - 1))][i - 1]);
mn[j][i] = min(mn[j][i - 1], mn[j + (1 << (i - 1))][i - 1]);
}
}
int q;
cin>>q;
auto get_max = [&](int l, int r) -> int{
int len = __lg(r - l + 1);
return max(mx[l][len], mx[r - (1 << len) + 1][len]);
};
auto get_min = [&](int l, int r) -> int{
int len = __lg(r - l + 1);
return min(mn[l][len], mn[r - (1 << len) + 1][len]);
};
auto find_first_grt = [&](int l, int r, int tar) -> int{
if(mx[r][0] > tar) return r;
l--;
while(l + 1 < r){
int m = (l + r) / 2;
if(get_max(m, r) > tar) l = m;
else r = m;
}
return l;
};
auto find_first_sm = [&](int l, int r, int tar) -> int{
if(mn[l][0] <= tar) return l;
r++;
while(l + 1 < r){
int m = (l + r) / 2;
if(get_min(l, m) <= tar) r = m;
else l = m;
}
return r;
};
while(q--){
int x;
cin>>x;
int stp = lower_bound(a.begin(), a.end(), x) - a.begin();
if(stp == n) stp--;
if(stp != 0 && x - a[stp - 1] <= a[stp] - x) stp--;
int l = stp, r = stp, ans = abs(x - a[stp]);
int d = 0;
while(true){
if(l == 0 || r == n - 1){
ans += a[n - 1] - a[0];
break;
}
ans += a[r] - a[l];
if(d == 0){
int tmp = find_first_grt(0, l - 1, a[r + 1]);
ans += a[l] - a[tmp + 1];
l = tmp + 1;
}
else{
int tmp = find_first_sm(r + 1, n - 1, a[l - 1]);
ans += a[tmp - 1] - a[r];
r = tmp - 1;
}
d ^= 1;
}
cout<<ans<<"\n";
}
}
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