Submission #945252

#	Time	Username	Problem	Language	Result	Execution time	Memory
945252		vjudge1	Sum Zero (RMI20_sumzero)	C++17	61 / 100	517 ms	50164 KiB

sumzero

#include <bits/stdc++.h>
using namespace std;

namespace std {

template <int D, typename T>
struct Vec : public vector<Vec<D - 1, T>> {
    static_assert(D >= 1, "Dimension must be positive");
    template <typename... Args>
    Vec(int n = 0, Args... args) : vector<Vec<D - 1, T>>(n, Vec<D - 1, T>(args...)) {}
};

template <typename T>
struct Vec<1, T> : public vector<T> {
    Vec(int n = 0, T val = T()) : std::vector<T>(n, val) {}
};

/* Example
    Vec<4, int64_t> f(n, k, 2, 2); // = f[n][k][2][2];
    Vec<2, int> adj(n); // graph
*/

template <class Fun>
class y_combinator_result {
    Fun fun_;

   public:
    template <class T>
    explicit y_combinator_result(T &&fun) : fun_(std::forward<T>(fun)) {}

    template <class... Args>
    decltype(auto) operator()(Args &&...args) {
        return fun_(std::ref(*this), std::forward<Args>(args)...);
    }
};

template <class Fun>
decltype(auto) y_combinator(Fun &&fun) {
    return y_combinator_result<std::decay_t<Fun>>(std::forward<Fun>(fun));
}

/* Example
    auto fun = y_combinator([&](auto self, int x) -> void {
        self(x + 1);
    });
*/

}  // namespace std

int32_t main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    int n;
    cin >> n;
    vector<int> a(n + 1);
    for (int i = 1; i <= n; i++) cin >> a[i];
    map<int64_t, int> mp;
    vector<vector<int>> prv(__lg(n) + 1, vector<int>(n + 1, -1));
    mp[0] = 0;
    int64_t sum = 0;
    for (int i = 1; i <= n; i++) {
        sum += a[i];
        if (mp.count(sum)) {
            prv[0][i] = mp[sum];
            prv[0][i] = max(prv[0][i], prv[0][i - 1]);
        } else {
            prv[0][i] = prv[0][i - 1];
        }
        mp[sum] = i;
    }
    for (int i = 1; i <= __lg(n); i++) {
        for (int j = 0; j <= n; j++) {
            if (prv[i - 1][j] == -1) continue;
            prv[i][j] = prv[i - 1][prv[i - 1][j]];
        }
    }
    int q;
    cin >> q;
    while (q--) {
        int l, r;
        cin >> l >> r;
        l--;
        int res = 0;
        for (int i = __lg(n); i >= 0; i--) {
            if (r >= l && prv[i][r] >= l) r = prv[i][r], res += 1 << i;
        }
        cout << res << '\n';
    }
}

• Subtask 1: 22 / 22
• Subtask 2: 39 / 39
• Subtask 3: 0 / 39