제출 #94458

#제출 시각아이디문제언어결과실행 시간메모리
94458aminraBitaro’s Party (JOI18_bitaro)C++14
100 / 100
1838 ms261608 KiB
//Smaug never desolated!! #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; const int MAXN = (int)100007; const int block = 320; const int infint = (int)1e8 + 3; const int MOD = (int)1e9 + 7; const ll inf = (ll)1e18; int n, m, q, bad[MAXN], dp[MAXN], input[MAXN], prv[MAXN]; pair<int, int> DP[MAXN][block], tmp[block]; vector<int> in[MAXN]; bool cmp(pair<int, int> a, pair<int, int> b) { return a.second > b.second; } inline void merge(int a, int b) { /*int sz = 0; vector<int> used; for (int i = 0; i < block; i++) tmp[i] = {-1, -1}; int ptr1 = 0, ptr2 = 0; while(sz < block && (ptr1 < block || ptr2 < block)) { while(ptr1 < block && DP[a][ptr1].first != -1 && prv[DP[a][ptr1].first]) ptr1++; while(ptr2 < block && DP[b][ptr2].first != -1 && prv[DP[b][ptr2].first]) ptr2++; pair<int, int> B = {-1, -1}; if(ptr2 != block && DP[b][ptr2].first != -1) B = DP[b][ptr2], B.second++; if(ptr1 != block && (ptr2 == block || cmp(DP[a][ptr1], B))) { tmp[sz] = DP[a][ptr1], ptr1++, sz++; int idx = DP[a][ptr1].first; if(idx != -1) prv[idx] = 1, used.push_back(idx); } else { tmp[sz] = B, ptr2++, sz++; int idx = B.first; if(idx != -1) prv[idx] = 1, used.push_back(idx); } } for (int i = 0; i < block; i++) DP[a][i] = tmp[i]; for (auto u : used) prv[u] = 0;*/ for (int i = 0; i < block; i++) tmp[i] = {-1, -1}; vector<pair<int, int> > all; int ptr1 = 0, ptr2 = 0; while(ptr1 < block || ptr2 < block) { pair<int, int> B = {-1, -1}; if(ptr2 != block && DP[b][ptr2].first != -1) B = DP[b][ptr2], B.second++; if(ptr1 < block && (ptr2 == block || cmp(DP[a][ptr1], B))) all.push_back(DP[a][ptr1++]); else all.push_back(B), ptr2++; } int sz = 0; for (auto u : all) if(u.first != -1 && !prv[u.first]) tmp[sz++] = u, prv[u.first] = 1; for (auto u : all) if(u.first != -1) prv[u.first] = 0; for (int i = 0; i < block; i++) DP[a][i] = tmp[i]; } int main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); cin >> n >> m >> q; for (int i = 0; i < m; i++) { int u, v; cin >> u >> v; in[v].push_back(u); } for (int i = 1; i <= n; i++) for (int j = 0; j < block; j++) DP[i][j] = {-1, -1}; DP[1][0] = {1, 0}; for (int i = 2; i <= n; i++) { DP[i][0] = {i, 0}; for (auto u : in[i]) merge(i, u); } for (int i = 0; i < q; i++) { int v, t; cin >> v >> t; for (int i = 0; i < t; i++) { cin >> input[i]; bad[input[i]] = 1; } if(t >= block) { memset(dp, -1, sizeof dp); dp[v] = 0; for (int i = v; i >= 1; i--) if(dp[i] != -1) for (auto u : in[i]) dp[u] = max(dp[u], dp[i] + 1); int ans = -1; for (int i = v; i >= 1; i--) if(!bad[i]) ans = max(ans, dp[i]); cout << ans << "\n"; } else { int ans = -1; for (int i = block - 1; i >= 0; i--) if(DP[v][i].first != -1 && !bad[DP[v][i].first]) ans = DP[v][i].second; cout << ans << "\n"; } for (int i = 0; i < t; i++) bad[input[i]] = 0; } }
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