This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define ff first
#define ss second
#define all(x) begin(x), end(x)
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define F0R(i, x) FOR(i, 0, x)
#define FORd(i, a, b) for(int i = (b)-1; i >= (a); i--)
#define F0Rd(i, x) FORd(i, 0, x)
const int MAX_N = 3e5+69;
const ll MOD = 1000000007;
const ll INF = 1e18;
int n, m, k;
int nums[MAX_N], tot[20];
pii val1[1 << 20];
pair<pii, pii> val2[1 << 20];
int main(int argc, const char * argv[]){
cin.tie(0)->sync_with_stdio(0);
cin.exceptions(cin.failbit);
cin >> n >> m; k = n/2;
F0R(i, n) F0R(j, m){
int x; cin >> x;
if(x) nums[i] ^= 1 << j;
tot[j] += x;
}
F0R(i, n) nums[i] ^= (1 << m)-1;
F0R(i, 1 << m) val1[i] = {-1, -1};
F0R(i, n){
if(~val1[nums[i]].ff) val1[nums[i]].ss = i;
else val1[nums[i]].ff = i;
}
F0R(i, m) F0R(msk, 1 << m) if(msk&(1 << i)){
vector<int> v;
v.push_back(val1[msk].ff), v.push_back(val1[msk].ss);
v.push_back(val1[msk^(1 << i)].ff), v.push_back(val1[msk^(1 << i)].ss);
sort(all(v)), reverse(all(v));
val1[msk^(1 << i)] = {v[0], v[1]};
}
F0R(msk, 1 << m){
if(~val1[msk].ff)
val2[msk].ff = {__builtin_popcount(msk), val1[msk].ff};
else val2[msk].ff = {0, -1};
if(~val1[msk].ss)
val2[msk].ss = {__builtin_popcount(msk), val1[msk].ss};
else val2[msk].ss = {0, -1};
}
F0R(i, m) F0R(msk, 1 << m) if(msk&(1 << i)){
vector<pii> v;
v.push_back(val2[msk].ff), v.push_back(val2[msk].ss);
v.push_back(val2[msk^(1 << i)].ff), v.push_back(val2[msk^(1 << i)].ss);
sort(all(v)), reverse(all(v));
int k = 2;
val2[msk] = {v[0], v[1]};
while(val2[msk].ff.ss == val2[msk].ss.ss)
val2[msk].ss = v[k++];
}
F0R(i, n){
int val = 0, ans = 0;
F0R(j, m){
if(tot[j] > k+1) ans++;
if(tot[j] == k+1){
if(!(nums[i]&(1 << j))) val ^= (1 << j);
else ans++;
}
if((nums[i]&(1 << j)) && tot[j] == k) val ^= (1 << j);
}
if(i == val2[val].ff.ss) cout << ans+val2[val].ss.ff << '\n';
else cout << ans+val2[val].ff.ff << '\n';
}
return 0;
}
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