# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
944522 | 2024-03-12T21:07:54 Z | rainboy | 제곱근 구하기 2 (gs13068_sqrt2) | C++17 | 1 ms | 420 KB |
#include <math.h> #include <stdio.h> long long abs_(long long a) { return a > 0 ? a : -a; } int main() { long long n, r; scanf("%lld", &n); r = sqrt(n); while (abs_(r * r - n) > abs_((r + 1) * (r + 1) - n)) r++; while (abs_(r * r - n) > abs_((r - 1) * (r - 1) - n)) r--; printf("%f\n", (double) r / 2 + (double) n / r / 2); return 0; }
Compilation message
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Correct | 1 ms | 416 KB | Output is correct |
2 | Correct | 0 ms | 348 KB | Output is correct |
3 | Correct | 0 ms | 348 KB | Output is correct |
4 | Correct | 0 ms | 344 KB | Output is correct |
5 | Correct | 0 ms | 348 KB | Output is correct |
6 | Correct | 0 ms | 420 KB | Output is correct |
7 | Correct | 1 ms | 348 KB | Output is correct |
8 | Correct | 0 ms | 348 KB | Output is correct |
9 | Correct | 0 ms | 348 KB | Output is correct |
10 | Correct | 0 ms | 348 KB | Output is correct |
11 | Correct | 0 ms | 348 KB | Output is correct |
12 | Correct | 0 ms | 420 KB | Output is correct |
13 | Correct | 0 ms | 348 KB | Output is correct |
14 | Correct | 0 ms | 344 KB | Output is correct |
15 | Correct | 0 ms | 348 KB | Output is correct |
16 | Correct | 0 ms | 348 KB | Output is correct |
17 | Correct | 0 ms | 348 KB | Output is correct |
18 | Correct | 0 ms | 348 KB | Output is correct |
19 | Correct | 0 ms | 344 KB | Output is correct |
20 | Correct | 0 ms | 348 KB | Output is correct |