# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
944515 | 2024-03-12T20:58:49 Z | rainboy | 제곱근 구하기 1 (gs13068_sqrt1) | C++17 | 1 ms | 604 KB |
#include <math.h> #include <stdio.h> int main() { long long n; int r; scanf("%lld", &n), r = sqrt(n); while ((long long) (r + 1) * (r + 1) <= n) r++; while ((long long) r * r > n) r--; printf("%f\n", r + (double) (n - (long long) r * r) / (r * 2 + 1)); return 0; }
Compilation message
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Correct | 1 ms | 344 KB | Output is correct |
2 | Correct | 0 ms | 348 KB | Output is correct |
3 | Correct | 0 ms | 348 KB | Output is correct |
4 | Correct | 0 ms | 348 KB | Output is correct |
5 | Correct | 0 ms | 416 KB | Output is correct |
6 | Correct | 0 ms | 348 KB | Output is correct |
7 | Correct | 0 ms | 348 KB | Output is correct |
8 | Correct | 0 ms | 348 KB | Output is correct |
9 | Correct | 1 ms | 604 KB | Output is correct |
10 | Correct | 0 ms | 348 KB | Output is correct |
11 | Correct | 0 ms | 348 KB | Output is correct |
12 | Correct | 0 ms | 416 KB | Output is correct |
13 | Correct | 0 ms | 348 KB | Output is correct |
14 | Correct | 0 ms | 348 KB | Output is correct |
15 | Correct | 0 ms | 348 KB | Output is correct |
16 | Correct | 0 ms | 348 KB | Output is correct |
17 | Correct | 0 ms | 348 KB | Output is correct |
18 | Correct | 0 ms | 348 KB | Output is correct |
19 | Correct | 0 ms | 348 KB | Output is correct |
20 | Correct | 0 ms | 348 KB | Output is correct |