제출 #943301

#제출 시각아이디문제언어결과실행 시간메모리
943301shoryu386Road Construction (JOI21_road_construction)C++17
65 / 100
10090 ms1073584 KiB
#include <bits/stdc++.h>
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

#define int long long

template <typename T>
using pbds_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;

main(){
	int n, k; cin >> n >> k;
	
	pair<int, int> arr[n];
	for (int x = 0; x < n; x++){
		cin >> arr[x].first >> arr[x].second;
	}
	
	//consider manhattan distance trick?
	for (int x = 0; x < n; x++){
		arr[x] = {arr[x].first + arr[x].second, arr[x].first - arr[x].second};
	}
	sort(arr, arr+n); //sorted by x-coord
	
	//now chebyshev distance, dist = max of difference
	
	//I want to bsearch, but bsearch only gives location of boundary; I need sum of boundary
	
	
	int l = 0, r = 4'000'000'000LL, ans = 4'000'000'000LL;
	while (l <= r){
		int m = (l+r)/2;
		int cnt = 0;
		
		
		pbds_multiset<int> ms;
		priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;
		for (int x = 0; x < n; x++){
			while (!pq.empty() && pq.top().first <= arr[x].first){
				ms.erase(ms.find_by_order(ms.order_of_key(arr[ pq.top().second ].second)));
				pq.pop();
			}
			cnt += ms.order_of_key(arr[x].second+m + 1) - ms.order_of_key(arr[x].second - m);
			
			ms.insert(arr[x].second);
			pq.push({arr[x].first+m+1, x});
		}
		
		if (cnt < k){
			l = m+1;
		}
		else{
			ans = m;
			r = m-1;
		}
	}
	
	
	vector<int> clown;
	for (int x = 0; x < n; x++){
		for (int y = x+1; y <= min(x+k+2, n-1); y++){
			if ( abs(arr[x].first - arr[y].first) > ans) break;
			
			clown.push_back( max( abs(arr[x].first - arr[y].first), abs(arr[x].second - arr[y].second) ) );
		}
	}
	
	sort(clown.begin(), clown.end());
	for (int x = 0; x < k; x++) cout << clown[x] << '\n';
}

컴파일 시 표준 에러 (stderr) 메시지

road_construction.cpp:13:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
   13 | main(){
      | ^~~~
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