#include<bits/stdc++.h>
#define st first
#define nd second
#define pb push_back
#define ppb pop_back
#define ppf pop_front
#define umax(x,y) x=max(x,y)
#define umin(x,y) x=min(x,y)
#define ll long long
#define ii pair<int,int>
#define iii pair<ii,int>
#define iiii pair<ii,ii>
#define sz(x) ((int) x.size())
#define orta ((bas+son)/2)
#define all(x) x.begin(),x.end()
#define dbgs(x) cerr<<(#x)<<" --> "<<(x)<<" "
#define dbg(x) cerr<<(#x)<<" --> "<<(x)<<endl;getchar()
#define pw(x) (1<<(x))
#define inf 1000000000000000000ll
#define MOD 1000000007
#define N 200005
#define M 25005
#define LOG 20
#define KOK 450
#define EPS 0.00001
using namespace std;
int n,r,q,cnt,t,x,y,tot;
int sub[N],be[N],en[N],c[N],fr[M],id[N],has[N];
int ans1[450][M],ans2[M][450];
vector<int> v[N],qu[M];
vector<ii> add[M];
int solve(int x,int y) {
int j=-1;
int cur=0;
int ans=0;
for(int i=0;i<sz(add[x]);i++) {
while(j+1<sz(qu[y]) && qu[y][j+1]<add[x][i].st) {
++j;
ans+=cur;
}
cur+=add[x][i].nd;
}
return ans;
}
void dfs2(int node,int ata,int curid) {
sub[node]=0;
for(int i:v[node]) {
dfs2(i,node,curid);
sub[node]+=sub[i];
}
ans2[c[node]][curid]+=sub[node];
sub[node]+=(c[node]==has[curid]);
}
void dfs1(int node,int ata,int curid) {
ans1[curid][c[node]]+=cnt;
cnt+=(c[node]==has[curid]);
for(int i:v[node]) {
dfs1(i,node,curid);
}
cnt-=(c[node]==has[curid]);
}
void dfs(int node,int ata) {
be[node]=++t;
for(int i:v[node]) dfs(i,node);
en[node]=t;
}
int main() {
//freopen("regions.gir","r",stdin);
//freopen("regions.cik","w",stdout);
//freopen("input.txt","r",stdin);
scanf("%d %d %d",&n,&r,&q);
scanf("%d",c+1);
for(int i=2;i<=n;i++) {
scanf("%d %d",&x,c+i);
v[x].pb(i);
}
dfs(1,0);
for(int i=1;i<=n;i++) {
fr[c[i]]++;
}
for(int i=1;i<=r;i++) {
if(fr[i]>=KOK) {
has[++tot]=i;
id[i]=tot;
}
}
for(int i=1;i<=n;i++) {
if(fr[c[i]]<KOK) {
qu[c[i]].pb(be[i]);
add[c[i]].pb({be[i]+1,1});
add[c[i]].pb({en[i]+1,-1});
}
}
for(int i=1;i<=r;i++) {
sort(all(qu[i]));
sort(all(add[i]));
}
for(int i=1;i<=tot;i++) {
dfs1(1,0,i);
dfs2(1,0,i);
}
while(q--) {
scanf("%d %d",&x,&y);
if(fr[x]>=KOK) {
printf("%d\n",ans1[id[x]][y]);
}
else if(fr[y]>=KOK) {
printf("%d\n",ans2[x][id[y]]);
}
else {
printf("%d\n",solve(x,y));
}
fflush(stdout);
}
}
