Submission #941620

#TimeUsernameProblemLanguageResultExecution timeMemory
941620shoryu386A Difficult(y) Choice (BOI21_books)C++17
30 / 100
2760 ms608 KiB
#include <bits/stdc++.h> #include "books.h" using namespace std; void solve(int N, int K, long long A, int S) { // TODO implement this function //k books, sum of A typedef long long ll; //x, x+1, x+2, x+3, x+4, x+5... and so on int extrasum = 0; for (int x = 0; x < K; x++){ extrasum += x; } //we want A <= x*K + extrasum <= 2*A //x*K + extrasum >= A //x*K >= A-extrasum //x >= (A-extrasum)/K ll target = (A - extrasum)/K + ((A - extrasum)%K != 0); //to do: check rounding if (A - extrasum <= 0) {impossible(); return;} int l = 1, r = N+1-K, ans = N+1-K; while (l <= r){ int m = (l+r)/2; ll res = skim(m); if (res >= target){ r = m-1; ans = m; } else{ l = m+1; } } vector<pair<int, ll>> items; set<int> indicesInside; for (int x = max(1, ans-10); x < min(N+1, ans+K); x++){ items.push_back({x, skim(x)}); indicesInside.insert(x); } for (int x = 1; x <= 10; x++){ if (indicesInside.count(x) == 0) items.push_back({x, skim(x)}), indicesInside.insert(x); } for (int bm = 0; bm < (1<<items.size()); bm++){ if (__builtin_popcount(bm) != K) continue; ll sum = 0; for (int x = 0; x < (int)items.size(); x++){ if (bm & (1<<x)){ sum += items[x].second; } } if (A <= sum && sum <= 2LL*A){ vector<int> indices; for (int x = 0; x < (int)items.size(); x++){ if (bm & (1<<x)){ indices.push_back(items[x].first); } } answer(indices); return; } } impossible(); }
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