Submission #941571

#TimeUsernameProblemLanguageResultExecution timeMemory
941571shoryu386A Difficult(y) Choice (BOI21_books)C++17
0 / 100
1 ms612 KiB
#include <bits/stdc++.h> #include "books.h" using namespace std; void solve(int N, int K, long long A, int S) { // TODO implement this function //k books, sum of A typedef long long ll; //x, x+1, x+2, x+3, x+4, x+5... and so on int extrasum = 0; for (int x = 0; x < K; x++){ extrasum += x; } //we want A <= x*K + extrasum <= 2*A //x*K + extrasum >= A //x*K >= A-extrasum //x >= (A-extrasum)/K ll target = (A - extrasum)/K + ((A - extrasum)%K != 0); //to do: check rounding if (A - extrasum <= 0) {impossible(); return;} int l = 1, r = N+1-K, ans = N+1-K; while (l <= r){ int m = (l+r)/2; ll res = skim(m); if (res >= target){ r = m-1; ans = m; } else{ l = m+1; } } ll sum = 0; deque<int> vals; for (int x = ans; x < ans + K; x++){ int res = skim(x); sum += res; vals.push_back(res); } if (ans != N+1-K) assert(sum >= A); int lowest = ans; for (int x = 0; x < min(10, lowest-1); x++){ if (sum <= 2LL*A){ vector<int> res; for (int x = lowest; x < lowest+K; x++) res.push_back(x); answer(res); } else{ sum -= vals.back(); vals.pop_back(); lowest--; int v = skim(lowest); vals.push_front(v); sum += v; } } if (sum <= 2LL*A){ vector<int> res; for (int x = lowest; x < lowest+K; x++) res.push_back(x); answer(res); } impossible(); }
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