이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<iostream>
#include<vector>
#include<queue>
using namespace std;
const int N = 1e3 + 5;
char grid[N][N];
int left_[N][N], right_[N][N], up[N][N], down[N][N];
vector<int> G[N * N], port[N * N];
int dist[N * N];
int r, c, m;
int dx[] = {1, -1, 0, 0};
int dy[] = {0, 0, 1, -1};
bool valid(int x, int y)
{
return (x > 0 && y > 0 && x <= r && y <= c && grid[x][y] != '#');
}
void bfs(int v, int u)
{
for(int i = 0; i < N * N; i++)
dist[i] = N * N + 10;
queue<int> q;
vector<int> portals;
q.push(v);
dist[v] = 0;
while(q.size())
{
int w = q.front();
q.pop();
bool hold = false;
for(int i : port[w])
{
portals.push_back(i);
hold |= (w == i);
}
for(int k : G[w])
{
if(dist[w] + 1 < dist[k])
{
dist[k] = dist[w] + 1;
q.push(k);
}
}
if(hold)
{
for(int i : portals)
if(dist[w] + 1 < dist[i])
{
dist[i] = dist[w] + 1;
q.push(i);
}
portals.clear();
}
}
//for(int i = 1; i <= r; i++)
//for(int j = 1; j <= c; j++)
// cout << dist[i * m + j] << " \n"[j == c];
cout << dist[u] << endl;
}
int main()
{
cin >> r >> c;
for(int i = 1; i <= r; i++)
for(int j = 1; j <= c; j++)
cin >> grid[i][j];
m = c + 2;
for(int i = 1; i <= r; i ++)
for(int j = 1; j <= c; j ++)
{
if(grid[i][j] == '#') continue;
int ij = i * m + j;
for(int n = 0; n < 4; n++)
{
int ni = i + dx[n], nj = j + dy[n];
int nij = ni * m + nj;
if(valid(ni, nj))
G[ij].push_back(nij);
}
}
for(int i = 1; i <= r; i ++)
{
int p = 0;
for(int j = 1; j <= c; j++)
{
if(grid[i][j] == '#') p = j;
left_[i][j] = p;
}
int n = c + 1;
for(int j = c; j >= 1; j--)
{
if(grid[i][j] == '#') n = j;
right_[i][j] = n;
}
}
for(int j = 1; j <= c; j ++)
{
int p = 0;
for(int i = 1; i <= r; i ++)
{
if(grid[i][j] == '#') p = i;
up[i][j] = p;
}
int n = r + 1;
for(int i = r; i >= 1; i--)
{
if(grid[i][j] == '#') n = i;
down[i][j] = n;
}
}
for(int i = 1; i <= r; i ++)
for(int j = 1; j <= c; j++)
{
if(grid[i][j] == '#') continue;
int idx = i * m + j;
int idx1 = i * m + left_[i][j] + 1;
int idx2 = i * m + right_[i][j] - 1;
int idx3 = (up[i][j] + 1) * m + j;
int idx4 = (down[i][j] - 1) * m + j;
port[idx].push_back(idx1);
port[idx].push_back(idx2);
port[idx].push_back(idx3);
port[idx].push_back(idx4);
}
int v = 0, u = 0;
for(int i = 1; i <= r; i++)
for(int j = 1; j <= c; j++)
if(grid[i][j] == 'S')
v = i * m + j;
else if(grid[i][j] == 'C')
u = i * m + j;
bfs(v, u);
return 0;
}
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