Submission #940882

#TimeUsernameProblemLanguageResultExecution timeMemory
940882velislavgarkovCouncil (JOI23_council)C++14
100 / 100
2652 ms690968 KiB
#include <iostream> using namespace std; const int MAXN=3e5+10; const int MAXM=(1<<20); //#define endl '\n' struct Answer { int ans1, ind1; int ans2, ind2; }; int n, M; int a[MAXN], op[MAXN], cnt[32]; pair <int, int> idx[MAXM][25], base[MAXM]; Answer dp[MAXM][25]; bool mem1[MAXM][25], mem2[MAXM][25]; bool fbit(int x, int bit) { return (x & (1<<bit)); } Answer find_best (Answer res, int s, int i) { if (s>=res.ans1) { if (res.ind2!=i) { res.ans2=res.ans1; res.ind2=res.ind1; } else res.ans2=res.ind2=0; res.ans1=s; res.ind1=i; } else if (s>=res.ans2 && i!=res.ind1) { res.ans2=s; res.ind2=i; } return res; } pair <int,int> find_idx(int mask, int m) { if (m==-1) return base[mask]; if (mem1[mask][m]) return idx[mask][m]; mem1[mask][m]=true; idx[mask][m]=find_idx(mask,m-1); if (!(mask & (1 << m))) { pair <int, int> s=find_idx((mask ^ (1 << m)),m-1); if (idx[mask][m].first==0) idx[mask][m]=s; else if (idx[mask][m].second==0) { if (s.first && s.first!=idx[mask][m].first) idx[mask][m].second=s.first; else if (s.second && s.second!=idx[mask][m].first) idx[mask][m].second=s.second; } } return idx[mask][m]; } Answer find_dp(int mask, int m) { if (m==-1) { Answer res={0,0,0,0}; pair <int,int> cur=find_idx(mask,M-1); int s=__builtin_popcount(mask); if (cur.first!=0) { res.ans1=s; res.ind1=cur.first; } if (cur.second!=0 && cur.second!=res.ind1) { res.ans2=s; res.ind2=cur.second; } return res; } if (mem2[mask][m]) return dp[mask][m]; mem2[mask][m]=true; dp[mask][m]=find_dp(mask,m-1); if ((mask & (1 << m))) { Answer res=find_dp((mask ^ (1 << m)),m-1); dp[mask][m]=find_best(dp[mask][m],res.ans1,res.ind1); dp[mask][m]=find_best(dp[mask][m],res.ans2,res.ind2); } //cout << "dp " << mask << ' ' << m << ' ' << dp[mask][m].ans1 << ' ' << dp[mask][m].ans2 << ' ' << dp[mask][m].ind1 << ' ' << dp[mask][m].ind2 << endl; return dp[mask][m]; } int main () { ios::sync_with_stdio(false); cin.tie(nullptr); cin >> n >> M; int bit; for (int i=1;i<=n;i++) { for (int j=0;j<M;j++) { cin >> bit; a[i]+=(bit<<j); cnt[j]+=bit; } op[i]=(((1 << M) - 1) & (~a[i])); if (base[op[i]].first==0) base[op[i]].first=i; else base[op[i]].second=i; } for (int i=1;i<=n;i++) { int ans=0, mask=0; for (int j=0;j<M;j++) { if (cnt[j]>=n/2+2) ans++; else if (cnt[j]==n/2+1) { if (!fbit(a[i],j)) ans++; else mask+=(1<<j); } else if (cnt[j]==n/2 && !fbit(a[i],j)) mask+=(1<<j); } Answer res=find_dp(mask,M-1); if (res.ind1!=i) ans+=res.ans1; else ans+=res.ans2; cout << ans << endl; } return 0; }
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