#include<bits/stdc++.h>
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define pb push_back
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define mispertion ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#define F first
#define S second
#define getlast(s) (*s.rbegin())
#define debg cout << "OK\n"
const ld PI = 3.1415926535;
const int N = 100000+1;
const int M = 7e6 + 1;
int mod = 998244353;
const int infi = INT_MAX;
const ll infl = LLONG_MAX;
const int P = 31;
int mult(int a, int b) {
return a * 1LL * b % mod;
}
int sum(int a, int b) {
if (a + b < 0)
return a + b + mod;
if (a + b >= mod)
return a + b - mod;
return a + b;
}
ll binpow(ll a, ll n) {
if (n == 0)
return 1;
if (n % 2 == 1) {
return binpow(a, n - 1) * a % mod;
} else {
ll b = binpow(a, n / 2);
return b * b % mod;
}
}
struct Line{
ll k, b, ind;
};
ll intersect(Line x, Line y){
return (ll)ceil((ld)(y.b - x.b) / (ld)(x.k - y.k));
}
struct LineContainer : multiset<Line, less<>> {
vector<pair<ll, Line>> st;
void add(ll k, ll m, ll ind) {
if(sz(st) == 0){
st.pb({-infi, {k, m, ind}});
return;
}
while(k == st.back().S.k || intersect({k, m, ind}, st.back().S) < st.back().F){
if(k == st.back().S.k && st.back().S.b > m)
return;
st.pop_back();
}
st.push_back({intersect({k, m, ind}, st.back().S), {k, m, ind}});
}
pair<ll, ll> query(ll x) {
int lo = 0, hi = sz(st);
while(lo + 1 < hi){
int m = (lo + hi) / 2;
if(st[m].F <= x)
lo = m;
else
hi = m;
}
return {st[lo].S.k * x + st[lo].S.b, st[lo].S.ind};
}
};
ll a[N], pr[N];
int p[N][201];
vector<ll> cdp(N, 0LL), pdp(N, 0LL);
void solve(){
int n, k;
cin >> n >> k;
pr[0] = 0;
for(int i = 1; i <= n; i++)
cin >> a[i], pr[i] = pr[i - 1] + a[i];
for(int l = 1; l <= k; l++){
LineContainer lc;
lc.add(pr[l], pdp[l] - pr[l] * pr[l], l);
cdp[l] = 0;
p[l][l] = 0;
for(int i = l + 1; i <= n; i++){
pair<ll, ll> ret = lc.query(pr[i]);
cdp[i] = ret.F;
p[i][l] = ret.S;
lc.add(pr[i], pdp[i] - pr[i] * pr[i], i);
}
pdp = cdp;
}
int cur = k, cn = n;
vector<int> ans = {};
while(cur > 0){
ans.pb(p[cn][cur]);
cn = p[cn][cur];
cur--;
}
cout << cdp[n] << '\n';
reverse(all(ans));
for(auto e : ans)
cout << e << ' ';
}
signed main() {
mispertion;
int t = 1;
//cin >> t;
while(t--){
solve();
}
return 0;
}
