제출 #939292

#제출 시각아이디문제언어결과실행 시간메모리
939292vjudge1Dango Maker (JOI18_dango_maker)C++17
100 / 100
291 ms159344 KiB
#include<bits/stdc++.h>

using namespace std;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
#define int ll
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define pb push_back
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define mispertion ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#define F first
#define S second
#define getlast(s) (*s.rbegin())
#define debg cout << "OK\n"

const ld PI = 3.1415926535;
const int N = 3000+1;
const int M = 7e6 + 1;
int mod = 998244353;
const int infi = INT_MAX;
const ll infl = LLONG_MAX;
const int P = 31;

int mult(int a, int b) {
    return a * 1LL * b % mod;
}

int sum(int a, int b) { 
    if (a + b < 0)
        return a + b + mod;
    if (a + b >= mod)
        return a + b - mod;
    return a + b;
}

ll binpow(ll a, ll n) {
    if (n == 0)
        return 1;
    if (n % 2 == 1) {
        return binpow(a, n - 1) * a % mod;
    } else {
        ll b = binpow(a, n / 2);
        return b * b % mod;
    }
}
int n, m, l[N][N], r[N][N];
char c[N][N];

void solve(){
    cin >> n >> m;
    for(int i = 1; i <= n; i++)
        for(int j = 1; j <= m; j++)
            cin >> c[i][j];
    for(int i = 1; i <= n; i++){
        for(int j = 1; j <= m; j++){
            if(i + 2 <= n){
                if(c[i][j] == 'R' && c[i + 1][j] == 'G' && c[i + 2][j] == 'W')
                    l[i][j] = 1;
            }
            if(j + 2 <= m){
                if(c[i][j] == 'R' && c[i][j + 1] == 'G' && c[i][j + 2] == 'W')
                    r[i][j] = 1;
            }
        }
    }
    int ans = 0;
    for(int s = 2; s <= n + m; s++){
        vector<int> dpl(min(s + 1, m + 1), 0);
        vector<int> dpr(min(s + 1, m + 1), 0);
        for(int j = 1; j <= min(s, m); j++){
            int i = s - j;
            if(i < 1 || i > n){
                dpl[j] = dpl[j - 1];
                dpr[j] = dpr[j - 1];
                continue;
            }
            if(l[i][j]){
                dpl[j] = dpl[j - 1] + 1;
                if(j - 3 >= 0)
                    dpl[j] = max(dpl[j], dpr[j - 3] + 1);
            }else{
                dpl[j] = dpl[j - 1];
            }
            if(r[i][j]){
                dpr[j] = max(dpr[j - 1], dpl[j - 1]) + 1;
            }else{
                dpr[j] = dpr[j - 1];
            }
        }
        ans += max(dpr[min(s, m)], dpl[min(s, m)]);
    }
    cout << ans << '\n';
}   

signed main() {
    mispertion;
    int t = 1;
    //cin >> t;
    while(t--){
        solve();
    }
    return 0;
}
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