제출 #938874

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
938874		andrewp	Knapsack (NOI18_knapsack)	C++14	49 / 100	7 ms	604 KiB

knapsack

//Dedicated to my love, ivaziva
#define yes cout << "YES\n"
#define no cout << "NO\n"
#define here cerr<<"---------------------------------\n"
#define dbg(x) cerr<<#x<<": "<<x<<endl;
#include "bits/stdc++.h"
#define ll long long
#define ld long double
#define llinf 100000000000000000LL
#define pb push_back
#define popb pop_back
#define fi first
#define sc second
#define endl '\n'
#define pll pair<ll,ll>
#define pld pair<ld,ld>
#define all(a) a.begin(),a.end()
#define sz(s) (ll)(s.size())
#define ios ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);
#define mod 1000000007
using namespace std;
/*#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
typedef tree<int,null_type,less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_multiset;
ll add(ll x,ll y){
    if(x+y>=mod) return x+y-mod;
    return x+y;
}
ll sub(ll x,ll y){
    if(x-y<0) return x-y+mod;
    return x-y;
}
ll mul(ll x,ll y){
    ll res=(x*y)%mod;
    if(res<0) res+=mod;
    return res;
}
ll pw(ll x,ll y){
	ll ret=1,bs=x;
	for(;y;y>>=1){
		if(y&1) ret=mul(ret,bs);
		bs=mul(bs,bs);
	}
	return ret%mod;
}*/
#define maxn 2005
ll n,s;
ll v[maxn],w[maxn];
vector<pll> c[maxn];
ll dp1[maxn][2],dp2[maxn][2];
void tc(){
    cin >> s >> n;
    for(ll i = 1;i<=n;i++){
        ll vu,wu,k;
        cin >> vu >> wu >> k;
        c[wu].pb({vu,k});
    }
    ll id=1;
    for(ll i = 1;i<=s;i++){
        if(sz(c[i])==0) continue;
        sort(c[i].rbegin(),c[i].rend());
        ll mx=s/i;
        for(ll j = 0;j<sz(c[i]);j++){
            ll cnt=1;
            for(;cnt<=min(c[i][j].sc,mx);cnt++){
                v[id]=c[i][j].fi;
                w[id]=i;
                id++;
            }
        }
    }
    --id;
    n=id;
    for(ll j = 0;j<=s;j++){
        dp1[j][0]=0ll,dp1[j][1]=0ll;
        dp2[j][0]=0ll,dp2[j][1]=0ll;
    }
    dp1[0][0]=0;
    dp1[w[1]][1]=v[1];
    for(ll i = 2;i<=n;i++){
        for(ll j = 0;j<=s;j++){
            dp2[j][0]=max(dp1[j][0],dp1[j][1]);
            if(j+w[i]<=s){
                dp2[j+w[i]][1]=max(dp2[j+w[i]][1],dp1[j][0]+v[i]);
                dp2[j+w[i]][1]=max(dp2[j+w[i]][1],dp1[j][1]+v[i]);
            }
        }
        swap(dp1,dp2);
        for(ll j = 0;j<=s;j++){
            dp2[j][0]=0ll,dp2[j][1]=0ll;
        }
    }
    ll ans=0;
    for(ll i = 0;i<=s;i++){
        ans=max(ans,max(dp1[i][0],dp1[i][1]));
        ans=max(ans,max(dp2[i][0],dp2[i][1]));
    }
    cout<<ans<<endl;
}
int main(){
	ios
    int t; t = 1;
//    cin >> t;
    while(t--){
        tc();
    }
	return 0;
}

• Subtask 1: 12 / 12
• Subtask 2: 17 / 17
• Subtask 3: 20 / 20
• Subtask 4: 0 / 24
• Subtask 5: 0 / 27