제출 #937977

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
937977		kitlix	Dango Maker (JOI18_dango_maker)	C++17	33 / 100	160 ms	262172 KiB

dango_maker

#include <bits/stdc++.h>

using namespace std;

const int INF = 1e9;

vector<vector<int>> g;
vector<int> used, mt;
int timer = 1;

bool kuhn(int v) {
    if (used[v] == timer)
        return false;
    used[v] = timer;
    for (auto to : g[v]) {
        if (mt[to] == -1) {
            mt[v] = to;
            mt[to] = v;
            return true;
        }
    }
    for (auto to : g[v]) {
        if (kuhn(mt[to])) {
            mt[v] = to;
            mt[to] = v;
            return true;
        }
    }
    return false;
}

signed main() {
    ios_base::sync_with_stdio(0), cin.tie(0);
    int n, m;
    cin >> n >> m;
    vector<vector<int>> table(n, vector<int>(m));
    for (auto& r : table) {
        string s;
        cin >> s;
        for (int j = 0; j < m; ++j) {
            if (s[j] == 'R')
                r[j] = 0;
            else if (s[j] == 'G')
                r[j] = 1;
            else
                r[j] = 2;
        }
    }
    g.resize(2 * n * m), used.resize(n * m), mt.resize(2 * n * m, -1);
    auto encode = [&](int x, int y) {
        return x * m + y;
        };
    int allcnt = 0;
    vector<vector<int>> has_vert(n, vector<int>(m));
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
            if (table[i][j])
                continue;
            if (i + 2 < n) {
                if (table[i + 1][j] == 1 && table[i + 2][j] == 2) {
                    allcnt += 1;
                    has_vert[i][j] = 1;
                }
            }
        }
    }
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
            if (table[i][j])
                continue;
            if (j + 2 < m) {
                if (table[i][j + 1] == 1 && table[i][j + 2] == 2) {
                    allcnt += 1;
                    if (has_vert[i][j])
                        g[encode(i, j)].push_back(n * m + encode(i, j));
                    if (i - 1 >= 0 && j + 1 < m && has_vert[i - 1][j + 1])
                        g[encode(i, j)].push_back(n * m + encode(i - 1, j + 1));
                    if (i - 2 >= 0 && j + 2 < m && has_vert[i - 2][j + 2])
                        g[encode(i, j)].push_back(n * m + encode(i - 2, j + 2));
                }
            }
        }
    }
    for (int i = 0; i < n * m; ++i)
        if (kuhn(i))
            timer += 1;
    int bipmt = 0;
    for (int i = 0; i < n * m; ++i)
        if (mt[i] != -1)
            bipmt += 1;
    cout << allcnt - bipmt;
}

• Subtask 1: 13 / 13
• Subtask 2: 20 / 20
• Subtask 3: 0 / 67