Submission #937806

#	Time	Username	Problem	Language	Result	Execution time	Memory
937806		danikoynov	Teams (IOI15_teams)	C++14	21 / 100	4037 ms	18096 KiB

teams

#include "teams.h"
#include <bits/stdc++.h>
using namespace std;
const int maxn = 5e5 + 10;

struct segment
{
    int l, r;

    segment(int _l = 0, int _r = 0)
    {
        l = _l;
        r = _r;
    }
};

int n;
segment s[maxn];
void init(int N, int A[], int B[])
{
    n = N;
    for (int i = 1; i <= n; i ++)
        s[i] = segment(A[i - 1], B[i - 1]);
}

struct event
{
    int x, t, id;

    event(int _x = 0, int _t = 0, int _id = 0)
    {
        x = _x;
        t = _t;
        id = _id;
    }

};

bool cmp_event(event e1, event e2)
{
    if (e1.x != e2.x)
        return e1.x < e2.x;
    return e1.t < e2.t;
}

int dp[maxn];


int can(int M, int K[])
{

    for (int i = 0; i < M; i ++)
    {
        dp[i] = 0;
    }

    sort(K, K + M);
    for (int i = 0; i < M; i ++)
    {

    for (int j = 1; j <= n; j ++)
        if (s[j].l <= K[i] && s[j].r >= K[i])
        dp[i] ++;
    dp[i] -= K[i];

    for (int j = 0; j < i; j ++)
    {
        int cnt = 0;
        for (int d = 1; d <= n; d ++)
        {
            if (s[d].l <= K[j] && s[d].r >= K[j])
                continue;
            if (s[d].l <= K[i] && s[d].r >= K[i])
                cnt ++;
        }
        dp[i] = min(dp[i], dp[j] + cnt - K[i]);
    }
    if (dp[i] < 0)
        return 0;
    }

    return 1;


    /**vector < event > events;
    for (int i = 0; i < M; i ++)
    {
        events.push_back(event(K[i], 0, -1));
    }
    for (int i = 1; i <= n; i ++)
    {
        events.push_back(event(s[i].l, -1, i));
        events.push_back(event(s[i].r, 1, i));
    }

    sort(events.begin(), events.end(), cmp_event);

    set < pair < int, int > > act;
    for (event cur : events)
    {
        if (cur.t == -1)
        {
            act.insert({s[cur.id].r, cur.id});
        }
        else
        if (cur.t == 1)
        {
            if (act.find({s[cur.id].r, cur.id}) != act.end())
                act.erase({s[cur.id].r, cur.id});
        }
        else
        {
            if (act.size() < cur.x)
            {
                return 0;
            }
            for (int d = 0; d < cur.x; d ++)
                act.erase(act.begin());
        }
    }
    return 1;*/
}

• Subtask 1: 21 / 21
• Subtask 2: 0 / 13
• Subtask 3: 0 / 43
• Subtask 4: 0 / 23