이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "bits/stdc++.h"
#define F first
#define S second
#define ALL(a) a.begin() , a.end()
#ifndef ONLINE_JUDGE
#define OK cout << __LINE__ << "| "<< "---------------------------OK-----------------------" << endl;
#define deb(x) cout << __LINE__ << "| "<< #x << " = " << x << endl;
#else
#define OK
#define deb(x)
#endif
typedef long double ld;
typedef long long ll;
using namespace std ;
const ll N = 21 ;
const ll INF = 1e9;
const ll mod = 1e9 + 7 ;
const double eps = 1e-9 ;
const int dx[] = { 0 , 0 , 1 , -1, 1 , -1 , 1 , -1} , dy[] = {1 , -1 , 0 , 0 , 1 , 1, -1 , -1} ;
int n , m, a[N] , b[N];
pair<int,int> dp[1 << N];
void test_solve(int test_index){
cin >> n >> m;
for(int i = 1; i <=n ; i++){
cin >> a[i];
}
for(int i = 1; i <= m; i++){
cin >> b[i];
}
for(int msk = 1; msk < (1 << m); msk++){
for(int j = 0; j < m;j++){
if(msk & ( 1 << j)){
int k = dp[msk ^ (1 << j)].F , sm = dp[msk ^ (1 << j)].S + b[j + 1];
if(sm == a[k + 1]){
sm = 0;
k++;
}
if(dp[msk].F < k){
dp[msk] = {k , sm};
}
else if(dp[msk].F == k){
dp[msk] = {k , sm};
}
}
}
if(dp[msk].F == n){
cout << "YES" << endl;
return;
}
}
cout << "NO" << endl;
}
signed main(){
ios_base::sync_with_stdio(false) ;
cin.tie(0) ;
cout.tie(0);
int test = 1;
//cin >> test ;
for(int i = 1 ; i <= test ; i++){
// cout << "Case " << i << ": " ;
test_solve(i) ;
}
return 0;
}
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