Submission #937414

#	Time	Username	Problem	Language	Result	Execution time	Memory
937414		VinhLuu	Palembang Bridges (APIO15_bridge)	C++17	63 / 100	2064 ms	6652 KiB

bridge

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
 
#include <bits/stdc++.h>
//#define int long long
#define ll long long
#define fi first
#define se second
#define pb push_back
#define all(lmao) lmao.begin(), lmao.end()
 
using namespace std;
 
typedef pair<int,int> pii;
typedef tuple<int,int,int> tp;
const int N = 2e5 + 5;
const ll oo = 1e18;
const int mod = 1e9 + 7;
const int K = 1e5 + 5;
 
char P[N], Q[N];
int S[N], T[N], k, n;
ll ans, s[N];
vector<ll> vr;
vector<pii> h;
int cnt = 0;
 
namespace sub1{
    void solve(){
        ll ret = oo;
        for(int i = 1; i <= cnt << 1; i ++){
            for(int j = i + 1; j <= cnt << 1; j ++){
                ll kq = 0;
                for(auto [l, r] : h){
                    if(l <= vr[i - 1] && vr[i - 1] <= r) kq += 1 + vr[i - 1] - l + r - vr[i - 1];
                    else if(l <= vr[j - 1] && vr[j - 1] <= r) kq += 1 + vr[j - 1] - l + r - vr[j - 1];
                    else if(vr[i - 1] <= l && r <= vr[j - 1]) kq += 1 + min(l - vr[i - 1] + r - vr[i - 1], vr[j - 1] - l + vr[j - 1] - r);
                    else if(r <= vr[i - 1]) kq += 1 + vr[i - 1] - l + vr[i - 1] - r;
                    else kq += 1 + l - vr[j - 1] + r - vr[j - 1];
                }
                ret = min(ret, kq + ans);
            }
        }
        ans = ret;
    }
}
 
namespace sub2{
 
    ll cal(int i,int j){
        ll kq = 0;
        for(auto [l, r] : h){
            if(l <= i && i <= r) kq += 1 + i - l + r - i;
            else if(l <= j && j <= r) kq += 1 + j - l + r - j;
            else if(i <= l && r <= j) kq += 1 + min(l - i + r - i, j - l + j - r);
            else if(r <= i) kq += 1 + i - l + i - r;
            else kq += 1 + l - j + r - j;
        }
        return kq;
    }
    ll ck(int i){
        ll ret = oo;
        int l = vr[i - 1] + 1;
        int r = min((ll)1e9, vr[cnt * 2 - 1] + 1);
        while(l < r - 3 &&  1.0 * clock() / CLOCKS_PER_SEC <= 1.2){
            int m1 = l + (r - l)/3, m2 = r - (r - l)/3;
            ll u = cal(vr[i - 1], m1);
            ll v = cal(vr[i - 1], m2);
            if(u > v) l = m1; else r = m2;
            ret = min({ret, u, v});
        }
        for(int j = l; j <= r; j ++) ret = min(ret, cal(vr[i - 1], j));
        return ret;
    }
    void solve(){
        ll ret = oo;
        int le = 1, ri = 2 * cnt, mid1, mid2;
//        cerr << 1.0 * clock() / CLOCKS_PER_SEC << " j\n";
        while(le < ri - 3 && 1.0 * clock() / CLOCKS_PER_SEC <= 1.2){
            mid1 = le + (ri - le)/3, mid2 = ri - (ri - le)/3;
//            cerr << le << " " << ri << "f\n";
            ll u = ck(mid1);
            ll v = ck(mid2);
            if(u > v) le = mid1; else ri = mid2;
            ret = min({ret, u, v});
        }
        for(int i = le; i <= ri; i ++) ret = min(ret, ck(i));
        ans += ret;
//        for(int i = 1; i <= cnt * 2; i ++){
//            int l = vr[i - 1] + 1;
//            int r = min((int)1e9, vr[cnt * 2 - 1] + 1);
//            while(l < r - 2){
//                int m1 = l + (r - l)/3, m2 = r - (r - l)/3;
//                int u = cal(vr[i - 1], m1);
//                int v = cal(vr[i - 1], m2);
//                if(u > v) l = m1; else r = m2;
//                ret = min({ret, u, v});
//            }
//            for(int j = l; j <= r; j ++) ret = min(ret, cal(vr[i - 1], j));
////            cerr << i << " " << ret << "f\n";
//        }
//        ans = ret + ans;
    }
}
 
signed main(){
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
 
    #define task "v"
    if(fopen(task ".inp","r")){
        freopen(task ".inp","r",stdin);
        freopen(task ".out","w",stdout);
    }
 
    cin >> k >> n;
 
 
    for(int i = 1; i <= n; i ++){
        cin >> P[i] >> S[i] >> Q[i] >> T[i];
        if(P[i] == Q[i]){
            ans += abs(S[i] - T[i]);
            continue;
        }
        vr.pb(S[i]);
        vr.pb(T[i]);
        cnt++;
        if(S[i] > T[i]) swap(S[i], T[i]);
        h.pb({S[i], T[i]});
    }
    if(!vr.empty()){
        sort(vr.begin(), vr.end());
        for(int i = 1; i <= cnt * 2; i ++) s[i] = s[i - 1] + vr[i - 1];
        if(k == 1){
            ll kq = oo;
            ll lim = vr[cnt - 1];
            for(int j = max(vr[0], lim - (ll)0); j <= min(vr[2 * cnt - 1], lim + (ll)0); j ++){
                int i = lower_bound(all(vr), j) - vr.begin();
                if(i < 2 * cnt){
                    i++;
                }
                    kq = min(kq, cnt + 1ll * j * (i - 1) - 1ll * j * (1ll * 2 * cnt - i + 1) - s[i - 1] + s[cnt * 2] - s[i - 1]);
            }
            ans = ans + kq;
        }else{
//            if(n <= 100) sub1 :: solve();
//            else
                sub2 :: solve();
        }
    }
    cout << ans;
 
}

Compilation message (stderr)

bridge.cpp: In function 'int main()':
bridge.cpp:111:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  111 |         freopen(task ".inp","r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
bridge.cpp:112:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  112 |         freopen(task ".out","w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 8 / 8
• Subtask 2: 14 / 14
• Subtask 3: 9 / 9
• Subtask 4: 32 / 32
• Subtask 5: 0 / 37