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답안 #937385

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
937385 2024-03-04T01:51:50 Z VinhLuu Palembang Bridges (APIO15_bridge) C++17
63 / 100
 2000 ms 6744 KB 
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

#include <bits/stdc++.h>
//#define int long long
#define ll long long
#define fi first
#define se second
#define pb push_back
#define all(lmao) lmao.begin(), lmao.end()

using namespace std;

typedef pair<int,int> pii;
typedef tuple<int,int,int> tp;
const int N = 2e5 + 5;
const ll oo = 1e18;
const int mod = 1e9 + 7;
const int K = 1e5 + 5;

char P[N], Q[N];
int S[N], T[N], k, n;
ll ans, s[N];
vector<ll> vr;
vector<pii> h;
int cnt = 0;

namespace sub1{
    void solve(){
        ll ret = oo;
        for(int i = 1; i <= cnt << 1; i ++){
            for(int j = i + 1; j <= cnt << 1; j ++){
                ll kq = 0;
                for(auto [l, r] : h){
                    if(l <= vr[i - 1] && vr[i - 1] <= r) kq += 1 + vr[i - 1] - l + r - vr[i - 1];
                    else if(l <= vr[j - 1] && vr[j - 1] <= r) kq += 1 + vr[j - 1] - l + r - vr[j - 1];
                    else if(vr[i - 1] <= l && r <= vr[j - 1]) kq += 1 + min(l - vr[i - 1] + r - vr[i - 1], vr[j - 1] - l + vr[j - 1] - r);
                    else if(r <= vr[i - 1]) kq += 1 + vr[i - 1] - l + vr[i - 1] - r;
                    else kq += 1 + l - vr[j - 1] + r - vr[j - 1];
                }
                ret = min(ret, kq + ans);
            }
        }
        ans = ret;
    }
}

namespace sub2{

    ll cal(int i,int j){
        ll kq = 0;
        for(auto [l, r] : h){
            if(l <= i && i <= r) kq += 1 + i - l + r - i;
            else if(l <= j && j <= r) kq += 1 + j - l + r - j;
            else if(i <= l && r <= j) kq += 1 + min(l - i + r - i, j - l + j - r);
            else if(r <= i) kq += 1 + i - l + i - r;
            else kq += 1 + l - j + r - j;
        }
        return kq;
    }
    ll ck(int i){
        ll ret = oo;
        int l = vr[i - 1] + 1;
        int r = min((ll)1e9, vr[cnt * 2 - 1] + 1);
        while(l < r - 3 &&  1.0 * clock() / CLOCKS_PER_SEC <= 1.8){
            int m1 = l + (r - l)/3, m2 = r - (r - l)/3;
            ll u = cal(vr[i - 1], m1);
            ll v = cal(vr[i - 1], m2);
            if(u > v) l = m1; else r = m2;
            ret = min({ret, u, v});
        }
        for(int j = l; j <= r; j ++) ret = min(ret, cal(vr[i - 1], j));
        return ret;
    }
    void solve(){
        ll ret = oo;
        int le = 1, ri = 2 * cnt, mid1, mid2;
//        cerr << 1.0 * clock() / CLOCKS_PER_SEC << " j\n";
        while(le < ri - 3 && 1.0 * clock() / CLOCKS_PER_SEC <= 1.8){
            mid1 = le + (ri - le)/3, mid2 = ri - (ri - le)/3;
//            cerr << le << " " << ri << "f\n";
            ll u = ck(mid1);
            ll v = ck(mid2);
            if(u > v) le = mid1; else ri = mid2;
            ret = min({ret, u, v});
        }
        for(int i = le; i <= ri; i ++) ret = min(ret, ck(i));
        ans += ret;
//        for(int i = 1; i <= cnt * 2; i ++){
//            int l = vr[i - 1] + 1;
//            int r = min((int)1e9, vr[cnt * 2 - 1] + 1);
//            while(l < r - 2){
//                int m1 = l + (r - l)/3, m2 = r - (r - l)/3;
//                int u = cal(vr[i - 1], m1);
//                int v = cal(vr[i - 1], m2);
//                if(u > v) l = m1; else r = m2;
//                ret = min({ret, u, v});
//            }
//            for(int j = l; j <= r; j ++) ret = min(ret, cal(vr[i - 1], j));
////            cerr << i << " " << ret << "f\n";
//        }
//        ans = ret + ans;
    }
}

signed main(){
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    #define task "v"
    if(fopen(task ".inp","r")){
        freopen(task ".inp","r",stdin);
        freopen(task ".out","w",stdout);
    }

    cin >> k >> n;


    for(int i = 1; i <= n; i ++){
        cin >> P[i] >> S[i] >> Q[i] >> T[i];
        if(P[i] == Q[i]){
            ans += abs(S[i] - T[i]);
            continue;
        }
        vr.pb(S[i]);
        vr.pb(T[i]);
        cnt++;
        if(S[i] > T[i]) swap(S[i], T[i]);
        h.pb({S[i], T[i]});
    }
    if(!vr.empty()){
        sort(vr.begin(), vr.end());
        for(int i = 1; i <= cnt * 2; i ++) s[i] = s[i - 1] + vr[i - 1];
        if(k == 1){
            ll kq = oo;
            ll lim = vr[cnt - 1];
            for(int j = max(vr[0], lim - (ll)1e5); j <= min(vr[2 * cnt - 1], lim + (ll)1e5); j ++){
                int i = lower_bound(all(vr), j) - vr.begin();
                if(i < 2 * cnt){
                    i++;
                }
                    kq = min(kq, cnt + 1ll * j * (i - 1) - 1ll * j * (1ll * 2 * cnt - i + 1) - s[i - 1] + s[cnt * 2] - s[i - 1]);
            }
            ans = ans + kq;
        }else{
//            if(n <= 100) sub1 :: solve();
//            else
                sub2 :: solve();
        }
    }
    cout << ans;

}

Compilation message

bridge.cpp: In function 'int main()':
bridge.cpp:112:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  112 |         freopen(task ".inp","r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
bridge.cpp:113:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  113 |         freopen(task ".out","w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2392 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 3 ms 2392 KB Output is correct
5 Correct 3 ms 2396 KB Output is correct
6 Correct 3 ms 2400 KB Output is correct
7 Correct 3 ms 2832 KB Output is correct
8 Correct 2 ms 2396 KB Output is correct
9 Correct 3 ms 2396 KB Output is correct
10 Correct 3 ms 2396 KB Output is correct
11 Correct 3 ms 2396 KB Output is correct

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 3 ms 2396 KB Output is correct
5 Correct 4 ms 2396 KB Output is correct
6 Correct 2 ms 2396 KB Output is correct
7 Correct 3 ms 2396 KB Output is correct
8 Correct 2 ms 2396 KB Output is correct
9 Correct 3 ms 2396 KB Output is correct
10 Correct 3 ms 2576 KB Output is correct
11 Correct 3 ms 2396 KB Output is correct
12 Correct 18 ms 6480 KB Output is correct
13 Correct 37 ms 6468 KB Output is correct
14 Correct 24 ms 6216 KB Output is correct
15 Correct 22 ms 4688 KB Output is correct
16 Correct 20 ms 6480 KB Output is correct
17 Correct 26 ms 6580 KB Output is correct
18 Correct 34 ms 6480 KB Output is correct
19 Correct 34 ms 6480 KB Output is correct
20 Correct 25 ms 6480 KB Output is correct
21 Correct 41 ms 6656 KB Output is correct

Subtask #3
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 0 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 1 ms 2396 KB Output is correct
5 Correct 1 ms 2396 KB Output is correct
6 Correct 1 ms 2396 KB Output is correct
7 Correct 1 ms 2396 KB Output is correct
8 Correct 1 ms 2396 KB Output is correct
9 Correct 1 ms 2396 KB Output is correct
10 Correct 2 ms 2396 KB Output is correct
11 Correct 1 ms 2396 KB Output is correct
12 Correct 2 ms 2560 KB Output is correct

Subtask #4
32.0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 2396 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 2 ms 2396 KB Output is correct
5 Correct 1 ms 2392 KB Output is correct
6 Correct 1 ms 2396 KB Output is correct
7 Correct 1 ms 2396 KB Output is correct
8 Correct 3 ms 2392 KB Output is correct
9 Correct 2 ms 2396 KB Output is correct
10 Correct 2 ms 2392 KB Output is correct
11 Correct 1 ms 2396 KB Output is correct
12 Correct 2 ms 2396 KB Output is correct
13 Correct 1 ms 2396 KB Output is correct
14 Correct 5 ms 2396 KB Output is correct
15 Correct 11 ms 2396 KB Output is correct
16 Correct 1 ms 2396 KB Output is correct
17 Correct 2 ms 2396 KB Output is correct
18 Correct 3 ms 2396 KB Output is correct
19 Correct 5 ms 2396 KB Output is correct
20 Correct 9 ms 2396 KB Output is correct
21 Correct 5 ms 2396 KB Output is correct
22 Correct 14 ms 2576 KB Output is correct
23 Correct 11 ms 2396 KB Output is correct
24 Correct 13 ms 2396 KB Output is correct

Subtask #5
0 / 37.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2392 KB Output is correct
2 Correct 1 ms 2392 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 2 ms 2396 KB Output is correct
5 Correct 1 ms 2396 KB Output is correct
6 Correct 1 ms 2396 KB Output is correct
7 Correct 1 ms 2396 KB Output is correct
8 Correct 2 ms 2396 KB Output is correct
9 Correct 2 ms 2396 KB Output is correct
10 Correct 2 ms 2396 KB Output is correct
11 Correct 2 ms 2396 KB Output is correct
12 Correct 2 ms 2396 KB Output is correct
13 Correct 1 ms 2396 KB Output is correct
14 Correct 3 ms 2580 KB Output is correct
15 Correct 11 ms 2396 KB Output is correct
16 Correct 1 ms 2392 KB Output is correct
17 Correct 2 ms 2396 KB Output is correct
18 Correct 3 ms 2396 KB Output is correct
19 Correct 5 ms 2396 KB Output is correct
20 Correct 9 ms 2576 KB Output is correct
21 Correct 5 ms 2396 KB Output is correct
22 Correct 13 ms 2396 KB Output is correct
23 Correct 11 ms 2396 KB Output is correct
24 Correct 12 ms 2392 KB Output is correct
25 Correct 48 ms 6744 KB Output is correct
26 Correct 953 ms 6648 KB Output is correct
27 Execution timed out 2058 ms 6480 KB Time limit exceeded
28 Halted 0 ms 0 KB -