이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <bits/stdc++.h>
#define int long long
#define ll long long
#define fi first
#define se second
#define pb push_back
#define all(lmao) lmao.begin(), lmao.end()
using namespace std;
typedef pair<int,int> pii;
typedef tuple<int,int,int> tp;
const int N = 2e5 + 5;
const int oo = 1e18;
const int mod = 1e9 + 7;
const int K = 1e5 + 5;
char P[N], Q[N];
int S[N], T[N], k, n, ans, s[N];
vector<int> vr;
vector<pii> h;
int cnt = 0;
namespace sub1{
void solve(){
int ret = oo;
for(int i = 1; i <= cnt << 1; i ++){
for(int j = i + 1; j <= cnt << 1; j ++){
int kq = 0;
for(auto [l, r] : h){
if(l <= vr[i - 1] && vr[i - 1] <= r) kq += 1 + vr[i - 1] - l + r - vr[i - 1];
else if(l <= vr[j - 1] && vr[j - 1] <= r) kq += 1 + vr[j - 1] - l + r - vr[j - 1];
else if(vr[i - 1] <= l && r <= vr[j - 1]) kq += 1 + min(l - vr[i - 1] + r - vr[i - 1], vr[j - 1] - l + vr[j - 1] - r);
else if(r <= vr[i - 1]) kq += 1 + vr[i - 1] - l + vr[i - 1] - r;
else kq += 1 + l - vr[j - 1] + r - vr[j - 1];
}
ret = min(ret, kq + ans);
}
}
ans = ret;
}
}
namespace sub2{
int cal(int i,int j){
int kq = 0;
for(auto [l, r] : h){
if(l <= i && i <= r) kq += 1 + i - l + r - i;
else if(l <= j && j <= r) kq += 1 + j - l + r - j;
else if(i <= l && r <= j) kq += 1 + min(l - i + r - i, j - l + j - r);
else if(r <= i) kq += 1 + i - l + i - r;
else kq += 1 + l - j + r - j;
}
return kq;
}
void solve(){
int ret = oo;
for(int i = 1; i <= cnt * 2; i ++){
int l = vr[i - 1] + 1;
int r = min((int)1e9, vr[cnt * 2 - 1] + 1);
int mid, pos = cal(vr[i - 1], vr[i - 1] + 1);
while(l < r - 2){
int m1 = l + (r - l)/3, m2 = r - (r - l)/3;
int u = cal(vr[i - 1], m1);
int v = cal(vr[i - 1], m2);
if(u > v) l = m1; else r = m2;
ret = min({ret, u, v});
}
for(int j = l; j <= r; j ++) ret = min(ret, cal(vr[i - 1], j));
// cerr << i << " " << ret << "f\n";
}
ans = ret + ans;
}
}
signed main(){
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define task "v"
if(fopen(task ".inp","r")){
freopen(task ".inp","r",stdin);
freopen(task ".out","w",stdout);
}
cin >> k >> n;
for(int i = 1; i <= n; i ++){
cin >> P[i] >> S[i] >> Q[i] >> T[i];
if(P[i] == Q[i]){
ans += abs(S[i] - T[i]);
continue;
}
vr.pb(S[i]);
vr.pb(T[i]);
cnt++;
if(S[i] > T[i]) swap(S[i], T[i]);
h.pb({S[i], T[i]});
}
if(!vr.empty()){
sort(vr.begin(), vr.end());
int mx = 0;
for(int i = 1; i <= cnt * 2; i ++) mx = max(mx, vr[i - 1]), s[i] = s[i - 1] + vr[i - 1];
if(k == 1){
int kq = oo;
int lim = vr[cnt - 1];
for(int j = max(vr[0], lim - (int)1e5); j <= min(vr[2 * cnt - 1], lim + (int)1e5); j ++){
int i = lower_bound(all(vr), j) - vr.begin();
if(i < 2 * cnt){
i++;}
kq = min(kq, cnt + j * (i - 1) - j * (2 * cnt - i + 1) - s[i - 1] + s[cnt * 2] - s[i - 1]);
}
ans = ans + kq;
}else{
// if(n <= 100) sub1 :: solve();
// else
sub2 :: solve();
}
}
cout << ans;
}
컴파일 시 표준 에러 (stderr) 메시지
bridge.cpp: In function 'void sub2::solve()':
bridge.cpp:66:16: warning: unused variable 'mid' [-Wunused-variable]
66 | int mid, pos = cal(vr[i - 1], vr[i - 1] + 1);
| ^~~
bridge.cpp:66:21: warning: unused variable 'pos' [-Wunused-variable]
66 | int mid, pos = cal(vr[i - 1], vr[i - 1] + 1);
| ^~~
bridge.cpp: In function 'int main()':
bridge.cpp:86:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
86 | freopen(task ".inp","r",stdin);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
bridge.cpp:87:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
87 | freopen(task ".out","w",stdout);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
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