이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int MAXN = 5007;
const ll INF = 1e18 + 7;
const int logo = 20;
const int off = 1 << logo;
ll inv[MAXN][MAXN], dp[MAXN], c[MAXN][MAXN];
//lesrig[y][x] - koliko brojeva je manje od y nadesno a oni su >= x
int lesrig[MAXN][MAXN], p[MAXN], a[MAXN], arr[MAXN];
ll vl(ll x){
return (ll)x * (x - 1) / (ll)2;
}
void solve(){
int n;
cin >> n;
for(int i=1; i<=n; i++) cin >> arr[i];
for(int L=1; L<=n; L++){
int cp = 1;
for(int i=1; i<=n; i++) if(arr[i] >= L){
a[cp] = arr[i];
p[arr[i]] = cp++;
}
ll su1 = 0, su0 = 0;
int id = 1;
for(int R=L; R<=n; R++, id++){
int cur = a[id];
if(cur < R) su1 -= p[cur];
else if(cur > R) su0 += p[cur];
if(cur != R){
if(p[R] <= id) su0 -= p[R];
else su1 += p[R];
}
c[L][R] = su1 - su0;
}
}
for(int i=0; i<=n; i++) p[i] = 0;
for(int pos=n; pos; pos--){
int cur = arr[pos];
for(int x=1; x<=n; x++) lesrig[cur][x] = p[cur - 1] - p[x - 1];
for(int i=cur; i<=n; i++) p[i]++;
}
for(int R=1; R<=n; R++){
for(int L=1; L<R; L++){
inv[L][R] = inv[L][R - 1] + lesrig[R][L];
}
}
dp[0] = 0;
for(int i=1; i<=n; i++) dp[i] = INF;
for(int R=1; R<=n; R++){
for(int L=0; L<R; L++){
int len = R - L;
dp[R] = min(dp[R], dp[L] + vl(len) - inv[L + 1][R] + c[L + 1][R]);
}
}
cout << dp[n] << "\n";
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int tt = 1;
//cin >> tt;
while(tt--) solve();
return 0;
}
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