Submission #936078

#TimeUsernameProblemLanguageResultExecution timeMemory
936078GrindMachineBoxes with souvenirs (IOI15_boxes)C++17
15 / 100
2097 ms440 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "boxes.h" long long delivery(int n, int k, int L, int A[]) { vector<int> a; rep(i,n) a.pb(A[i]); sort(all(a)); reverse(all(a)); while(!a.empty() and !a.back()) a.pop_back(); reverse(all(a)); if(a.empty()) return 0; n = sz(a); a.insert(a.begin(),0); ll oans = inf2; auto d = [&](ll x, ll y){ if(x > y) swap(x,y); ll dis = y-x; return min(dis,L-dis); }; do{ ll curr = 0; ll pos = 0; rep1(i,n){ if(i%k == 1 or k == 1){ curr += d(pos,0); pos = 0; } curr += d(pos,a[i]); pos = a[i]; } curr += d(pos,0); amin(oans,curr); } while(next_permutation(a.begin()+1,a.begin()+n+1)); return oans; ll ans = inf2; rep(f,n+1){ ll cost = 0; ll b = n-f; for(int i = k; i <= f; i += k){ cost += a[i]; cost += min(a[i],L-a[i]); } if(f%k){ cost += a[f]; cost += min(a[f],L-a[f]); } for(int i = k; i <= b; i += k){ cost += L-a[n-i+1]; cost += min(a[n-i+1],L-a[n-i+1]); } if(b%k){ cost += L-a[n-b+1]; cost += min(a[n-b+1],L-a[n-b+1]); } // cout << f << " " << cost << endl; cout << f << " " << cost << endl; amin(ans,cost); } cout << ans << endl; cout << oans << endl; // assert(ans == oans); return ans; }
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