제출 #930662

#제출 시각아이디문제언어결과실행 시간메모리
930662KiaRez건물 4 (JOI20_building4)C++17
100 / 100
202 ms45488 KiB
/* IN THE NAME OF GOD */ #include <bits/stdc++.h> // #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") // #pragma GCC optimize("O3") // #pragma GCC optimize("unroll-loops") using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef pair<int, int> pii; typedef long double ld; #define F first #define S second #define Mp make_pair #define pb push_back #define pf push_front #define size(x) ((ll)x.size()) #define all(x) (x).begin(),(x).end() #define kill(x) cout << x << '\n', exit(0); #define fuck(x) cout << "(" << #x << " , " << x << ")" << endl #define endl '\n' const int N = 1e6+23, lg = 18; ll Mod = 1e9+7; //998244353; inline ll MOD(ll a, ll mod=Mod) {a%=mod; (a<0)&&(a+=mod); return a;} inline ll poww(ll a, ll b, ll mod=Mod) { ll ans = 1; a=MOD(a, mod); while (b) { if (b & 1) ans = MOD(ans*a, mod); b >>= 1; a = MOD(a*a, mod); } return ans; } int n, a[N], b[N]; pii dp[2][N]; string str; pii merge(pii v, pii u) { return Mp(min(v.F, u.F), max(v.S, u.S)); } void solve(int bt, int id, int cnt) { if(id==0) return; if(bt==1)str.pb('B'); else str.pb('A'); if(bt==0) { if(a[id]>=a[id-1] && dp[0][id-1].F<=(n/2-cnt-1) && dp[0][id-1].S>=(n/2-cnt-1)) { solve(0, id-1, cnt+1); return; } solve(1, id-1, cnt+1); } else { if(b[id]>=a[id-1] && dp[0][id-1].F<=(n/2-cnt) && dp[0][id-1].S>=(n/2-cnt)) { solve(0, id-1, cnt); return; } solve(1, id-1, cnt); } } int main () { ios_base::sync_with_stdio(false), cin.tie(0); cin>>n; n*=2; for(int i=1; i<=n; i++) cin>>a[i]; for(int i=1; i<=n; i++) cin>>b[i]; dp[0][0] = dp[1][0] = {0, 0}; for(int i=1; i<=n; i++) { dp[0][i] = dp[1][i] = {1e9, -1e9}; if(a[i]>=a[i-1] && a[i]>=b[i-1]) dp[0][i] = merge(dp[0][i-1], dp[1][i-1]); else if(a[i]>=a[i-1]) dp[0][i] = dp[0][i-1]; else if(a[i]>=b[i-1]) dp[0][i] = dp[1][i-1]; dp[0][i].F++, dp[0][i].S++; if(b[i]>=a[i-1] && b[i]>=b[i-1]) dp[1][i] = merge(dp[0][i-1], dp[1][i-1]); else if(b[i]>=a[i-1]) dp[1][i] = dp[0][i-1]; else if(b[i]>=b[i-1]) dp[1][i] = dp[1][i-1]; } if(dp[0][n].F<=n/2 && dp[0][n].S>=n/2) { solve(0, n, 0); } else if(dp[1][n].F<=n/2 && dp[1][n].S>=n/2) { solve(1, n, 0); } else { kill(-1); } reverse(all(str)); cout<<str<<endl; return 0; }
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