# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
930561 | Baizho | XOR Sum (info1cup17_xorsum) | C++14 | 1636 ms | 16088 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
// #pragma GCC optimize("Ofast,unroll-loops,fast-math")
// #pragma GCC target("popcnt")
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll,ll> pll;
#define sz size()
#define ff first
#define ss second
#define all(a) a.begin(),a.end()
#define pb push_back
const int mod = ll(1e9)+7; //(b + (a%b)) % b (to mod -1%(10^9+7) correctly in c++ its -1 but its suppose to be 10^9+6
const ll MOD = 998244353; // (a%mod)*(binpow(b,mod-2,mod) = (a/b)%mod
const int N = ll(4e5)+100;
const int M = ll(2e5) + 100;
const long long inf = 5e18;
const long double eps = 1e-15L;
ll lcm(ll a, ll b) { return (a / __gcd(a,b))*b; }
ll binpow(ll a, ll b, ll m) { ll res=1; a %= m; while(b>0){ if(b&1)res=(res * a) % m; a=(a * a) % m; b/=2; } return res%m;}
void Freopen(string Key){ freopen((Key+".in").c_str(), "r", stdin); freopen((Key+".out").c_str(), "w", stdout); }
#define int ll
void Baizho() {
int n; cin>>n;
int a[n + 1], b[n + 1];
for(int i = 1; i <= n; i ++) cin>>a[i];
int ans = 0;
for(int k = 0; k < 29; k ++) {
for(int i = 1; i <= n; i ++) b[i] = a[i] % (1ll << (k + 1));
sort(b + 1, b + n + 1);
int cnt = 0, p1 = n + 1, p2 = n, p3 = n + 1, p4 = n;
for(int i = 1; i <= n; i ++) {
p1 = max(p1, i + 1);
while(p1 - 1 >= i && b[i] + b[p1 - 1] >= (1 << k)) p1 --;
p2 = max(p2, i);
while(p2 >= i && b[i] + b[p2] >= (1ll << (k + 1))) p2 --;
p3 = max(p3, i + 1);
while(p3 - 1 >= i && b[i] + b[p3 - 1] >= (1ll << k) + (1ll << (k + 1))) p3 --;
p4 = max(p4, i);
while(p4 >= i && b[i] + b[p4] >= (1ll << (k + 2))) p4 --;
// cout<<p1<<" "<<p2<<" "<<p3<<" "<<p4<<" "<<k<<" "<<i<<endl;
cnt += max(p2 - p1 + 1, 0ll);
cnt += max(p4 - p3 + 1, 0ll);
}
if(cnt & 1) {
ans ^= (1ll << k);
// cout<<k<<"\n";
}
}
cout<<ans<<"\n";
}
signed main() {
// Freopen("nondec");
ios_base::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
// precalc();
int ttt = 1;
// cin>>ttt;
for(int i=1; i<=ttt; i++) {Baizho(); }
}
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