이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// Success consists of going from failure to failure without loss of enthusiasm
#include <bits/stdc++.h>
using namespace std;
#define nl '\n'
#define f first
#define s second
#define mp make_pair
template<class T> using V = vector<T>;
using pi = pair<int, int>;
using vi = V<int>;
using vpi = V<pi>;
const int LG = 18;
int main() {
cin.tie(0)->sync_with_stdio(0);
int N; cin >> N;
/*vi L(N), R(N); for(int i = 0; i < N; i++) cin >> L[i] >> R[i];
int M = -1;
{
map<int, int> mp; int cur = 0;
for(auto& x : L) mp[x]++;
for(auto& x : R) mp[x]++;
for(auto& x : mp) x.second = cur++;
for(auto& x : L) x = mp[x];
for(auto& x : R) x = mp[x];
M = cur;
}*/
vpi A(N); for(int i = 0; i < N; i++) cin >> A[i].f >> A[i].s;
set<pi> S;
auto add = [&](pi x) {
auto it = S.lower_bound(x);
if (it != end(S)) {
pi y = *it;
if (x.s >= y.f) return false;
}
if (it != begin(S)) {
pi y = *prev(it);
if (y.s >= x.f) return false;
}
S.insert(x);
return true;
};
V<vi> nxt(N + 1, vi(LG, N)); int bnd = 0;
for(int i = 0; i < N; i++) {
// cout << i << " ==> " << L[i] << " " << R[i] << endl;
while(bnd < N && add(A[bnd])) bnd++;
nxt[i][0] = bnd;
// cout << i << " => " << bnd << endl;
S.erase(A[i]);
}
for(int x = N - 1; x >= 0; x--) {
for(int i = 1; i < LG; i++) nxt[x][i] = nxt[nxt[x][i-1]][i-1];
}
int Q; cin >> Q;
for(int q = 0; q < Q; q++) {
int l, r; cin >> l >> r; --l, --r;
int ans = 0;
for(int i = LG - 1; i >= 0; i--) {
if (nxt[l][i] <= r) { ans += (1 << i); l = nxt[l][i]; }
}
cout << ans + 1 << nl;
}
exit(0-0);
}
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