oj.uz

답안 #930023

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
930023 2024-02-18T09:01:55 Z gaga999 Balloons (CEOI11_bal) C++17
100 / 100
 103 ms 9320 KB 
#include <cstdio>
#include <stdio.h>
#include <iostream>
#include <math.h>
#include <vector>
#include <queue>
#include <stack>
#include <deque>
#include <algorithm>
#include <utility>
#include <set>
#include <map>
#include <stdlib.h>
#include <cstring>
#include <string.h>
#include <string>
#include <sstream>
#include <assert.h>
#include <climits>
#include <sstream>
#include <numeric>
#include <time.h>
#include <limits.h>
#include <list>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <iomanip>
#include <complex>
#include <chrono>
#include <fstream>
#include <functional>
#include <unistd.h>
// #pragma GCC optimize("Ofast,no-stack-protector")
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx,avx2,bmi,bmi2,lzcnt,popcnt")
#define lowbit(x) ((x) & -(x))
#define ml(a, b) ((1ll * (a) * (b)) % M)
#define tml(a, b) (a) = ((1ll * (a) * (b)) % M)
#define ad(a, b) ((0ll + (a) + (b)) % M)
#define tad(a, b) (a) = ((0ll + (a) + (b)) % M)
#define mi(a, b) ((0ll + M + (a) - (b)) % M)
#define tmi(a, b) (a) = ((0ll + M + (a) - (b)) % M)
#define tmin(a, b) (a) = min((a), (b))
#define tmax(a, b) (a) = max((a), (b))
#define iter(a) (a).begin(), (a).end()
#define riter(a) (a).rbegin(), (a).rend()
#define init(a, b) memset((a), (b), sizeof(a))
#define cpy(a, b) memcpy((a), (b), sizeof(a))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define pb emplace_back
#define mpr make_pair
#define ls(i) ((i) << 1)
#define rs(i) ((i) << 1 | 1)
#define INF 0x3f3f3f3f
#define NIF 0xc0c0c0c0
#define eps 1e-9
#define F first
#define S second
#define AC cin.tie(0)->sync_with_stdio(0)
using namespace std;
typedef long long llt;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<llt, llt> pll;
typedef complex<double> cd;
// const int M = 998244353;

// random_device rm;
// mt19937 rg(rm());
// default_random_engine rg(rm());
// uniform_int_distribution<int> rd(INT_MIN, INT_MAX);
// uniform_real_distribution<double> rd(0, M_PI);

void db() { cerr << "\n"; }
template <class T, class... U>
void db(T a, U... b) { cerr << a << " ", db(b...); }

inline char gc()
{
    const static int SZ = 1 << 16;
    static char buf[SZ], *p1, *p2;
    if (p1 == p2 && (p2 = buf + fread(p1 = buf, 1, SZ, stdin), p1 == p2))
        return -1;
    return *p1++;
}
void rd() {}
template <typename T, typename... U>
void rd(T &x, U &...y)
{
    x = 0;
    bool f = 0;
    char c = gc();
    while (!isdigit(c))
        f ^= !(c ^ 45), c = gc();
    while (isdigit(c))
        x = (x << 1) + (x << 3) + (c ^ 48), c = gc();
    f && (x = -x), rd(y...);
}

template <typename T>
void prt(T x)
{
    if (x < 0)
        putchar('-'), x = -x;
    if (x > 9)
        prt(x / 10);
    putchar((x % 10) ^ 48);
}

const int N = 2e5 + 5;
int pt[N];
double an[N];
vector<int> sk;

void f(int i)
{
    if (sk.empty())
        return;
    tmin(an[i], pow(pt[i] - pt[sk.back()], 2) / (4.0 * an[sk.back()]));
}

signed main()
{
    int n, x;
    rd(n);
    for (int i = 1; i <= n; i++)
        rd(pt[i], x), an[i] = x;
    for (int i = 1; i <= n; i++)
    {
        f(i);
        while (!sk.empty() && an[sk.back()] <= an[i])
            sk.pop_back(), f(i);
        sk.pb(i);
        printf("%.10lf\n", an[i]);
    }
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2492 KB 10 numbers

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2396 KB 2 numbers

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2392 KB 505 numbers

Subtask #4
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2392 KB 2000 numbers

Subtask #5
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 3160 KB 20000 numbers

Subtask #6
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 22 ms 4180 KB 50000 numbers
2 Correct 19 ms 4188 KB 49912 numbers

Subtask #7
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 52 ms 5712 KB 100000 numbers

Subtask #8
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 58 ms 6256 KB 115362 numbers
2 Correct 54 ms 6444 KB 119971 numbers

Subtask #9
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 92 ms 7252 KB 154271 numbers
2 Correct 68 ms 9320 KB 200000 numbers

Subtask #10
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 103 ms 8448 KB 200000 numbers
2 Correct 65 ms 9316 KB 199945 numbers