Submission #92900

#TimeUsernameProblemLanguageResultExecution timeMemory
92900stefdascaRobots (IOI13_robots)C++14
100 / 100
2040 ms24472 KiB
/* As it is usual for such problems, we can binary search the answer At each step, we will try to assign toys to the weak robots, then to the small robots. Since we will use a priority queue, checking will be done at each step in O(T log T) Therefore, the total complexity will be O(T log^2 T) */ #include"robots.h" #include<bits/stdc++.h> using namespace std; int putaway(int A, int B, int T, int X[], int Y[], int W[], int S[]) { int j = 0; sort(X, X+A); sort(Y, Y+B); vector<pair<int, int> >v; for(int i = 0; i < T; ++i) v.push_back({W[i], S[i]}); sort(v.begin(), v.end()); int b = 0; int e = 10000002; bool findd = 0; int ans = 0; while(b <= e) { int mid = (b + e) / 2; priority_queue<int>D; int ptra = 0; for(int i = 0; i < A; ++i) { while(ptra < T && X[i] > v[ptra].first) D.push(v[ptra].second), ++ptra; for(int j = 1; j <= mid && !D.empty(); ++j) D.pop(); } for(; ptra < T; ++ptra) D.push(v[ptra].second); for(int i = B-1; i >= 0; --i) { for(int j = 1; j <= mid && !D.empty(); ++j) if(D.top() < Y[i]) D.pop(); else break; } bool gg = (D.empty()); if(gg) findd = 1, ans = mid, e = mid - 1; else b = mid + 1; } if(!findd) return -1; return ans; }

Compilation message (stderr)

robots.cpp: In function 'int putaway(int, int, int, int*, int*, int*, int*)':
robots.cpp:16:9: warning: unused variable 'j' [-Wunused-variable]
     int j = 0;
         ^
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