이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define SQR(x) (1LL * ((x) * (x)))
#define MASK(i) (1LL << (i))
#define BIT(x, i) (((x) >> (i)) & 1)
#define fi first
#define se second
#define pb push_back
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define sz(s) (int)s.size()
#define prev __prev
#define next __next
#define left __left
#define right __right
#define mp make_pair
#define pii pair<int, int>
#define pll pair<ll, ll>
#define vi vector<int>
#define vll vector<ll>
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef unsigned int ui;
using namespace std;
const int mod = 1e9 + 7;
const int INF = 1e9 + 7;
const ll INFLL = (ll)2e18 + 7LL;
const ld PI = acos(-1);
const int dx[] = {1, -1, 0, 0, -1, 1, 1, -1};
const int dy[] = {0, 0, 1, -1, -1, -1, 1, 1};
template<class BUI, class TRONG>
bool minimize(BUI &x, const TRONG y){
if(x > y){
x = y;
return true;
} else return false;
}
template<class BUI, class TRONG>
bool maximize(BUI &x, const TRONG y){
if(x < y){
x = y;
return true;
} else return false;
}
/* Author : Bui Nguyen Duc Trong, Luong Van Chanh High School for the gifted*/
/* Template is copied by Trong */
/** Losing in Provincial Contests **/
/** TRYING HARDER**/
/** ORZ **/
/* -----------------[ MAIN CODE GOES HERE ]----------------- */
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int N = 1e5 + 10;
int n, k;
int a[N];
struct Line{
ll a, b;
Line() : a(0), b(0) {}
Line(ll a, ll b) : a(a), b(b) {}
ll f(ll x) { return a * x + b; }
};
struct ConvexHullTrick{
vector<Line> vec;
int iter = 0;
void reset(){
vec.clear();
iter = 0;
}
ld inter(Line A, Line B){
return (ld)(A.b - B.b) / (B.a - A.a);
}
void insertLine(Line l){
if(!vec.empty() && l.a == vec.back().a) maximize(vec.back().b, l.b);
else{
while(sz(vec) >= 2 && inter(l, vec.back()) <= inter(vec.back(), vec[sz(vec) - 2])) vec.pop_back();
vec.push_back(l);
}
}
ll query(ll x){
minimize(iter, sz(vec) - 1);
while(iter + 1 < sz(vec) && vec[iter + 1].f(x) >= vec[iter].f(x)) ++iter;
return vec[iter].f(x);
}
} cht;
ll f[N][202];
void solve(){
cin >> n >> k;
for(int i = 1; i <= n; i++){
cin >> a[i]; a[i] += a[i - 1];
}
for(int j = 1; j <= k; j++){
cht.reset();
for(int i = 1; i <= n; i++){
cht.insertLine(Line(a[i - 1], f[i - 1][j - 1] - 1LL * a[i - 1] * a[i - 1]));
f[i][j] = cht.query(a[i]);
}
}
int r = n;
vector<int> ans;
for(int i = k; i >= 1; i--){
bool found = 0;
for(int j = r; j >= 2; j--){
if(f[j - 1][i - 1] + 1LL * (a[r] - a[j - 1]) * a[j - 1] == f[r][i]){
ans.push_back(j - 1);
r = j - 1;
found = 1;
break;
}
}
assert(found);
}
cout << f[n][k] << '\n';
reverse(all(ans));
for(int x : ans) cout << x << ' '; cout << '\n';
}
/*
7 3
4 1 3 4 0 2 3
*/
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
const bool multitest = 0;
int tt = 1; if(multitest) cin >> tt;
while( tt-- ){
solve();
}
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
sequence.cpp: In function 'void solve()':
sequence.cpp:139:5: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
139 | for(int x : ans) cout << x << ' '; cout << '\n';
| ^~~
sequence.cpp:139:40: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
139 | for(int x : ans) cout << x << ' '; cout << '\n';
| ^~~~
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |