Submission #9275

#TimeUsernameProblemLanguageResultExecution timeMemory
9275myungwooPhibonacci (kriii2_P)C++14
1 / 4
0 ms1088 KiB
#include<stdio.h> #define mod 1000000007 typedef long long lld; struct term { lld a, b; term operator* (const term& c){ term k; k.a = a*c.b+b*c.a, k.b = b*c.b; k.a += a*c.a, k.b += a*c.a; return k; } term operator% (const lld c){ term k; k.a%=c, k.b%=c; return k; } }pn, pnk, dap; struct MAT{ lld m[2][2]; MAT operator * (const MAT &ot)const{ MAT ret={0, }; int i, j, k; for (i=0;i<2;i++) for (j=0;j<2;j++) for (k=0;k<2;k++) ret.m[i][j] = (ret.m[i][j]+(lld)m[i][k]*ot.m[k][j]%mod)%mod; return ret; } } P[40]; lld n, k; template <class T> T exp(T a, lld b){ if(b==1)return a; T im=exp(a,b/2); im=im*im, im=im%mod; if(b%2)im=im*a, im=im%mod; return im; } lld fibo(lld n){ MAT t ={1, 0, 0, 1}; int i; for (i=0;i<40;i++) if ((n>>i)&1) t = t*P[i]; return t.m[0][1]; } int main(){ lld i; MAT t ={1, 1, 1, 0}; P[0] = t; for (i=1;i<40;i++) P[i] = P[i-1]*P[i-1]; scanf("%lld%lld", &n, &k); pn.a=fibo(n), pn.b=fibo(n-1); pnk=exp(pn,k); dap.a=(pnk.a*exp(fibo(k),mod-2))%mod; dap.b=(pnk.b-dap.a*fibo(k-1))%mod; if(dap.b<0)dap.b+=mod; printf("%lld %lld", dap.a, dap.b); return 0; }
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