Submission #927145

#TimeUsernameProblemLanguageResultExecution timeMemory
927145Gromp15Commuter Pass (JOI18_commuter_pass)C++17
100 / 100
246 ms20112 KiB
#include <bits/stdc++.h> #define ll long long #define ar array #define db double #define all(x) x.begin(), x.end() #define sz(x) (int)x.size() using namespace std; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); #define rint(l, r) uniform_int_distribution<int>(l, r)(rng) template<typename T> bool ckmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; } template<typename T> bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; } void test_case() { int n, m; cin >> n >> m; int S, T, U, V; cin >> S >> T >> U >> V; vector<vector<ar<int, 2>>> adj(n+1); for (int i = 0; i < m; i++) { int x, y, w; cin >> x >> y >> w; adj[x].push_back({y, w}); adj[y].push_back({x, w}); } auto cost = [&](int sx) -> vector<ll> { vector<ll> d(n+1, 1e18); priority_queue<ar<ll, 2>, vector<ar<ll, 2>>, greater<ar<ll, 2>>> q; q.push({0, sx}); d[sx] = 0; while (q.size()) { auto [weight, v] = q.top(); q.pop(); if (weight != d[v]) continue; for (auto [u, w] : adj[v]) { if (ckmin(d[u], d[v] + w)) { q.push({d[u], u}); } } } return d; }; vector<ll> ds(cost(S)), dt(cost(T)), du(cost(U)), dv(cost(V)); // sort by order of dv vector<int> each(n); iota(all(each), 1); sort(all(each), [&](int x, int y) { return dv[x] < dv[y]; }); vector<int> where(n+1); for (int i = 0; i < n; i++) where[each[i]] = i; ll ans = 1e18, bst = ds[T]; vector<int> dp1(n+1, 1e9), dp2(n+1, 1e9); vector<int> o1(n); iota(all(o1), 1); sort(all(o1), [&](int x, int y) { return ds[x] < ds[y]; }); for (int v : o1) { // v --> s if (ds[v] + dt[v] != bst) continue; dp1[v] = where[v]; for (auto [u, w] : adj[v]) { if (dt[v] + w + ds[u] == bst) { ckmin(dp1[v], dp1[u]); } } } sort(all(o1), [&](int x, int y) { return dt[x] < dt[y]; }); for (int v : o1) { // v --> t if (ds[v] + dt[v] != bst) continue; dp2[v] = where[v]; for (auto [u, w] : adj[v]) { if (ds[v] + w + dt[u] == bst) { ckmin(dp2[v], dp2[u]); } } } for (int i = 1; i <= n; i++) { int idx = min(dp1[i], dp2[i]); if (idx < n) { ckmin(ans, du[i] + dv[each[idx]]); } } cout << min(ans, du[V]) << '\n'; } int main() { cin.tie(0)->sync_with_stdio(0); int t = 1; // cin >> t; while (t--) test_case(); }
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