제출 #926734

#제출 시각아이디문제언어결과실행 시간메모리
926734MtSakaAliens (IOI16_aliens)C++17
0 / 100
1 ms348 KiB
#include<bits/stdc++.h> #define overload(a,b,c,d,...) d #define rep1(a) for(ll _=0;_<(ll)a;++_) #define rep2(i,n) for(ll i=0;i<(ll)n;++i) #define rep3(i,l,r) for(ll i=(ll)l;i<(ll)r;++i) #define rep(...) overload(__VA_ARGS__,rep3,rep2,rep1)(__VA_ARGS__) #define rrep1(i,a) for(ll i=(ll)a-1;i>=0;--i) #define rrep2(i,a,b) for(ll i=(ll)b-1;i>=(ll)a;--i) #define rrep(...) overload(__VA_ARGS__,rrep2,rrep1)(__VA_ARGS__) #define all(x) (x).begin(),(x).end() #define rall(x) (x).rbegin(),(x).rend() #define pb push_back #define eb emplace_back using namespace std; using ll=long long; using ull=unsigned long long; using ld=long double; template<typename T,typename U>inline bool chmin(T&a,const U&b){return (a>b?a=b,true:false);} template<typename T,typename U>inline bool chmax(T&a,const U&b){return (a<b?a=b,true:false);} static constexpr ll mod1=998244353; static constexpr ll mod=1000000007; static constexpr ll inf=numeric_limits<ll>::max()/2; using vl=vector<ll>; struct RMQ{ private: int sz; vector<ll>seg; public: RMQ(int n):sz(1){ while(sz<n)sz<<=1; seg.resize(sz<<1,inf); } RMQ(const vector<ll>&v):sz(1){ while(sz<(int)v.size())sz<<=1; seg.resize(sz<<1,inf); rep(i,v.size())seg[i+sz]=v[i]; rrep(i,sz)seg[i]=min(seg[i<<1],seg[i<<1^1]); } ll prod(int l,int r)const{ l+=sz,r+=sz; ll ret=inf; while(l!=r){ if(l&1)chmin(ret,seg[l++]); if(r&1)chmin(ret,seg[--r]); l>>=1,r>>=1; } return ret; } }; ll take_photos(int n,int m,int k,vector<int>r,vector<int>c){ rep(i,n)if(r[i]>c[i])swap(r[i],c[i]); vl v(m,inf); rep(i,n)chmin(v[c[i]],r[i]); RMQ rmq(v); auto cost=[&](ll l,ll r)->ll { ll mi=rmq.prod(l,r); if(mi>=r)return 0LL; return (r-mi)*(r-mi); }; auto f=[&](ll lambda)->pair<ll,ll> { vector<pair<ll,ll>>dp(m+1,{inf,inf}); dp[0]={0,0}; vl idx(m+1,0); auto check=[&](ll l,ll r)->void { if(chmin(dp[r],pair<ll,ll>{dp[l].first+cost(l,r)+lambda,dp[l].second+1})){ idx[r]=l; } }; auto rec=[&](auto&&rec,ll l,ll r)->void { if(r-l<=1)return; ll mid=(l+r)/2; rep(i,idx[l],idx[r]+1)check(i,mid); rec(rec,l,mid); rep(i,l,mid+1)check(i,r); rec(rec,mid,r); }; check(0,m); rec(rec,0,m); return dp[m]; }; ll ng=-1,ok=m*m+1; while(ok-ng>1){ ll mid=(ok+ng)/2; auto [val,x]=f(mid); //cerr<<mid<<" "<<val<<" "<<x<<endl; if(x>k)ng=mid; else ok=mid; } auto [val,x]=f(ok); return val-k*ok; }
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