제출 #92631

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
92631		fire_tornado	회문 (APIO14_palindrome)	C++17	100 / 100	42 ms	37368 KiB

palindrome

#include<bits/stdc++.h>
using namespace std;

//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>
//using namespace __gnu_pbds;
//template<typename T>
//using ordered_set=tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;

#define MAX             100005
#define MOD             1000000007
#define eps             1e-6
int fx[] =              {1,-1,0,0};
int fy[] =              {0,0,1,-1};

#define FastRead        ios_base::sync_with_stdio(0);cin.tie(0);
#define fRead           freopen("in.txt","r",stdin);
#define fWrite          freopen ("out.txt","w",stdout);

#define ll              long long
#define ull             unsigned long long
#define ff              first
#define ss              second
#define pb              push_back
#define PI              acos(-1.0)
#define mk              make_pair
#define pii             pair<int,int>
#define pll             pair<ll,ll>
#define all(a)          a.begin(),a.end()

#define min3(a,b,c)     min(a,min(b,c))
#define max3(a,b,c)     max(a,max(b,c))
#define min4(a,b,c,d)   min(a,min(b,min(c,d)))
#define max4(a,b,c,d)   max(a,max(b,max(c,d)))

#define FOR(i,a,b)      for(int i=a;i<=b;i++)
#define ROF(i,a,b)      for(int i=a;i>=b;i--)
#define REP(i,b)        for(int i=0;i<b;i++)
#define IT(it,x)	    for(it=x.begin();it!=x.end();it++)

#define MEM(a,x)        memset(a,x,sizeof(a))
#define ABS(x)          ((x)<0?-(x):(x))
#define SQ(x)           ((x)*(x))

//// ***************************************************** TEMPLETE ***************************************************** ////


//const int NUM=1000005;bool flag[NUM];vector <int> prime;void sieve(){flag[1]=true;for(int i=4; i<NUM; i+=2)flag[i]=true;for(int i=3; i*i<=NUM; i+=2){if(!flag[i]){for(int j=i*i; j<NUM; j+=(i<<1))flag[j]=true;}}prime.pb(2);for(int i=3; i<NUM; i+=2)if(!flag[i])prime.pb(i);return;}

//int NOD(ll n){int div=1;for(int i=0; prime[i]*prime[i]<=n; i++){if(n%prime[i]==0){int cnt=0;while(n%prime[i]==0){n/=prime[i];cnt++;}div*=(cnt+1);}}if(n>1){div*=2;}return div;}

//ll BigMod(ll B,ll P,ll M){ll R=1;while(P>0){if(P & 1)R=(R*B)%M;P=P>>1;B=(B*B)%M;}return R%M;}


//// ***************************************************** NUMBER THEORY ***************************************************** ////


//inline void build(int L,int R,int pos){if(L==R){tree[pos]=arr[L];return;}int mid=(L+R)/2;build(L,mid,pos*2+1);build(mid+1,R,pos*2+2);tree[pos]=min(tree[pos*2+1],tree[pos*2+2]);return;}

//inline int query(int ql,int qr,int L,int R,int pos){if(ql>R or qr<L) return MAX;else if(ql<=L and qr>=R) return tree[pos];int mid=(L+R)/2;int p=query(ql,qr,L,mid,2*pos+1);int q=query(ql,qr,mid+1,R,2*pos+2);return min(p,q);}

//void updateRange(int b,int e,int L,int R,int pos,ll val){if(lazy[pos]!=0){tree[pos]+=(R-L+1)*lazy[pos];if(L!=R){lazy[2*pos+1]+=lazy[pos];lazy[2*pos+2]+=lazy[pos];}lazy[pos]=0;}if(L>R or L>e or R<b) return;if(L>=b and R<=e){tree[pos]+=(R-L+1)*val;if(L!=R){lazy[2*pos+1]+=val;lazy[2*pos+2]+=val;}return;}int mid=(L+R)/2;updateRange(b,e,L,mid,2*pos+1,val);updateRange(b,e,mid+1,R,2*pos+2,val);tree[pos]=tree[2*pos+1]+tree[2*pos+2];return;}

//ll getSum(int ql,int qr,int L,int R,int pos){if(lazy[pos]!=0){tree[pos]+=(R-L+1)*lazy[pos];if(L!=R){lazy[2*pos+1]+=lazy[pos];lazy[2*pos+2]+=lazy[pos];}lazy[pos]=0;}if(L>R or ql>R or qr<L) return 0;if(L>=ql and qr>=R) return tree[pos];int mid=(L+R)/2;return getSum(ql,qr,L,mid,2*pos+1)+getSum(ql,qr,mid+1,R,2*pos+2);}


//// ***************************************************** SEGMENT TREE ***************************************************** ////


//inline void bfs(int s){MEM(vis,0);vis[s]=1;queue<int>Q;Q.push(s);while(!Q.empty()){int x=Q.front();Q.pop();REP(i,V[x].size()){if(!vis[V[x][i]]){vis[V[x][i]]=1;Q.push(V[x][i]);}}}return;}

//int cell[100][100]; int d[100][100],vis[100][100];int row,col;inline void bfs(int sx,int sy){ MEM(vis,0);vis[sx][sy]=1;queue<pii>q; q.push(pii(sx,sy));while(!q.empty()){pii top=q.front();q.pop();for(int k=0; k<4; k++){int tx=top.ff+fx[k];int ty=top.ss+fy[k]; if(tx>=0 and tx<row and ty>=0 and ty<col and cell[tx][ty]!=-1 and vis[tx][ty]==0){vis[tx][ty]=1;d[tx][ty]=d[top.ff][top.ss]+1;q.push(pii(tx,ty)); }}}return;}

//inline void bi_dfs(int s,int c){if(vis[s]) return;vis[s]=1;color[s]=c;REP(i,V[s].size()) dfs(V[s][i],1-c);return;}

//struct point{int name,val;bool operator <(const point &p) const{return p.val < val;}};vector<int>V[105];int dis[105],cost[105][105];priority_queue<point>Q;void Dijkstra(int s){dis[s]=0;point get;get.name=s;get.val=0;Q.push(get);while(!Q.empty()){point tmp=Q.top();Q.pop();int now=tmp.name;REP(i,V[now].size()){int x=V[now][i];if(dis[now]+cost[now][x]<dis[x]){dis[x]=dis[now]+cost[now][x];get.name=x;get.val=dis[x];Q.push(get);}}}return;}

//struct edge{int u,v,w;bool operator < (const edge &p) const{return w < p.w;}};int pr[MAX];vector<edge>e;int find(int r){return pr[r]= (pr[r]==r) ? r:find(pr[r]);}int kruskal(int n){sort(e.begin(),e.end());FOR(i,1,n) pr[i]=i;int cnt=0,sum=0;REP(i,e.size()){int x=find(e[i].u);int y=find(e[i].v);if(x!=y){pr[x]=y;cnt++;sum+=e[i].w;if(cnt==n-1) break;}}return sum;}

//const int N=100005;int L[N],Pr[N],P[N][22];vector<int>V[N];void dfs(int s,int pre,int d){Pr[s]=pre;L[s]=d;for(int i:V[s]){if(i==pre) continue;dfs(i,s,d+1);}return;}void lca(){dfs(1,0,1); /*Source,Prev_Node(0/-1),Depth */ REP(i,N) REP(j,22) P[i][j]=1;FOR(i,1,N-1) P[i][0]=Pr[i];for(int j=1;(1<<j)<N;j++){REP(i,N){P[i][j]=P[P[i][j-1]][j-1];}}return;}int query(int p,int q){if(L[p]<L[q]) swap(p,q);ROF(i,21,0) if(L[P[p][i]]>=L[q]) p=P[p][i];if(p==q) return p;ROF(i,21,0){if(P[p][i]!=P[q][i]){p=P[p][i];q=P[q][i];}}return Pr[p];}

//// ***************************************************** GRAPH ***************************************************** ////

const int N=300005;
int tree[N][26],link[N],id,t;
ll len[N],freq[N];
char str[N];

void extend(int p)
{
    while(str[p-len[t]-1]!=str[p]) t=link[t];
    int x=link[t];
    while(str[p-len[x]-1]!=str[p]) x=link[x];
    int c=str[p]-'a';
    if(!tree[t][c])
    {
        tree[t][c]=++id;
        len[id]=len[t]+2;
        link[id]=len[id]==1?2:tree[x][c];
    }
    t=tree[t][c];
  	freq[t]++;
}

int main()
{
    int l=scanf("%s",str+1);
    l=strlen(str+1);

    len[1]=-1,link[1]=1;
    len[2]=0,link[2]=1;
    id=t=2;

    FOR(i,1,l) extend(i);

    ll m=0;
    ROF(i,id,3) {
        freq[link[i]]+=freq[i];
        m=max(m,freq[i]*len[i]);
    }
    printf("%lld\n",m);
}

• Subtask 1: 8 / 8
• Subtask 2: 15 / 15
• Subtask 3: 24 / 24
• Subtask 4: 26 / 26
• Subtask 5: 27 / 27