Submission #925980

#TimeUsernameProblemLanguageResultExecution timeMemory
925980GrindMachineDiversity (CEOI21_diversity)C++17
14 / 100
7002 ms9452 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,q; cin >> n >> q; vector<ll> a(n); rep(i,n) cin >> a[i]; { ll l,r; cin >> l >> r; } vector<ll> b; rep(i,n) b.pb(a[i]); sort(all(b)); b.resize(unique(all(b))-b.begin()); rep(i,n) a[i] = lower_bound(all(b),a[i])-b.begin(); ll m = sz(b); vector<ll> order(m); rep(i,m) order[i] = i; vector<ll> cnt(m); rep(i,n) cnt[a[i]]++; ll ans = inf2; do{ ll i = 1; ll cost = 0; trav(x,order){ ll c = cnt[x]; cost += i*(n-i+1); if(c > 1){ ll mx = n-(i+1)+1; ll mn = n-(i+c-1)+1; assert(mn <= mx); cost += mx*(mx+1)/2-mn*(mn-1)/2; } i += c; } amin(ans,cost); } while(next_permutation(all(order))); cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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