이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
#define S second
#define F first
#define all(x) (x).begin(),(x).end()
#define sz size()
#define Yes cout << "YES" << endl
#define No cout << "NO" << endl
#define pb(x) push_back(x);
#define endl '\n'
#define fast ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
const int N=3e5+7;
ll INF=INT_MAX,mod=1e9+7;
int TT=1;
ll power(ll x, unsigned int y)
{
    ll res = 1;
    x = x; // % mod;
    if (x == 0) return 0;
    while (y > 0)
    {
        if (y & 1) res = (res*x)  ; // % mod;
        y = y>>1;
        x = (x*x) ; // % mod;
    }
    return res;
}
string d[] = {"ne","da"};
void solve()
{
    int n , q; cin >> n >> q;
    string a, b; cin >> a >> b;
    ll sum = 0;
    bool bb = !(n&1);
    for(int i = 0; i < n; i++)
    {
        if((i%2)^bb) sum+=int(b[i]-a[i]);
        else sum-=int(b[i]-a[i]);
    }
    cout << d[(abs(sum)%26)==0] << endl;
    while(q--)
    {
        ll x; char c;
        cin >> x; cin >> c; x--;
        bool aa = ((x%2)^bb);
        if(aa) {sum-=int(b[x]-a[x]); a[x] = c; sum+=int(b[x]-a[x]);}
        else {sum+=int(b[x]-a[x]); a[x] = c; sum-=int(b[x]-a[x]);}
        cout << d[(abs(sum)%26)==0] << endl;
    }
}
int main(){
    //freopen("friday.in","r",stdin);
    //freopen("friday.out","w",stdout);
    fast;
    while(TT--)
        solve();
    return 0;
}
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