제출 #924076

#제출 시각아이디문제언어결과실행 시간메모리
924076dubabubaMatching (CEOI11_mat)C++14
100 / 100
683 ms65536 KiB
#include <iostream> #include <vector> #include <utility> using namespace std; #define MAX 1000000 #define INFTY 100000000 /* p1 is the original pattern from the problem statement, while * p is given from left to right, like the text t. */ int n, m; int p1[MAX + 1], p[MAX + 1], t[MAX + 1]; void read() { cin >> n >> m; for (int i = 1; i <= n; i++) { cin >> p1[i]; } for (int i = 1; i <= n; i++) p[p1[i]] = i; for (int i = 1; i <= m; i++) cin >> t[i]; } /* Segment trees, efficient implementation. */ pair<int, int> min_tree[1 << 21], max_tree[1 << 21]; int size; void init_trees() { size = 1; while (size <= n) size *= 2; for (int i = 0; i <= 2 * size - 1; i++) { min_tree[i] = make_pair(INFTY, -1); max_tree[i] = make_pair(-1, -1); } } int max_query(int v) { int ind = size + v; pair<int, int> res = make_pair(-1, -1); while (ind != 1) { if (ind % 2 == 1 && max_tree[ind - 1].first > res.first) res = max_tree[ind - 1]; ind /= 2; } return res.second; } int min_query(int v) { int ind = size + v; pair<int, int> res = make_pair(INFTY, -1); while (ind != 1) { if (ind % 2 == 0 && min_tree[ind + 1].first < res.first) res = min_tree[ind + 1]; ind /= 2; } return res.second; } void min_insert(pair<int, int> p) { int ind = size + p.first; min_tree[ind] = p; while (ind != 1) { ind /= 2; if (p.first < min_tree[ind].first) min_tree[ind] = p; } } void max_insert(pair<int, int> p) { int ind = size + p.first; max_tree[ind] = p; while (ind != 1) { ind /= 2; if (p.first > max_tree[ind].first) max_tree[ind] = p; } } int g[MAX + 1], h[MAX + 1]; /* Computes the g and h functions, as defined in the solution description, * using a segment tree. */ void compute_gh() { init_trees(); for (int i = 1; i <= n; i++) { g[i] = max_query(p[i]); h[i] = min_query(p[i]); min_insert(make_pair(p[i], i)); max_insert(make_pair(p[i], i)); } } int f[MAX + 1]; inline bool matches(int pos, int pos2) { if (g[pos] != -1 && p[pos2] <= p[pos2 - (pos - g[pos])]) return false; if (h[pos] != -1 && p[pos2] >= p[pos2 - (pos - h[pos])]) return false; return true; } inline bool matches_t(int pos, int pos2) { if (g[pos] != -1 && t[pos2] <= t[pos2 - (pos - g[pos])]) return false; if (h[pos] != -1 && t[pos2] >= t[pos2 - (pos - h[pos])]) return false; return true; } /* Computes the failure function of the pattern. */ void compute_f() { f[0] = f[1] = 0; int last = 0; for (int i = 2; i <= n; i++) { f[i] = last; while (last && !matches(last + 1, i)) last = f[last]; if (matches(last + 1, i)) last++; f[i] = last; } } vector<int> result; void matching() { int last = 0; for (int i = 1; i <= m; i++) { while (last && !matches_t(last + 1, i)) last = f[last]; if (matches_t(last + 1, i)) last++; if (last == n) { result.push_back(i - n + 1); last = f[last]; } } } void write() { cout << result.size() << endl; for (int i = 0; i < (int)result.size(); i++) { cout << result[i]; if (i < (int)result.size() - 1) cout << " "; } cout << endl; } int main() { ios_base::sync_with_stdio(0); read(); compute_gh(); compute_f(); matching(); write(); return 0; }
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