이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define ar array
#define db double
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define rint(l, r) uniform_int_distribution<int>(l, r)(rng)
template<typename T> bool ckmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; }
template<typename T> bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }
struct seg {
int n, N, S, T;
vector<int> size;
vector<ll> tree, lazy, tree2;
ll cost(ll x, ll y) {
return (ll)(x-y) * (x < y ? S : T);
}
seg(int s, int t, vector<int> &a) : n(sz(a)-1), N(1<<(__lg(n+1)+1)), S(s), T(t), size(2*N), tree(2*N), lazy(2*N), tree2(2*N) {
for (int i = 0; i <= n; i++) {
tree[i+N] = a[i], size[i+N] = 1;
if (i) tree2[i+N] = cost(a[i-1], a[i]);
}
for (int i = N-1; i >= 1; i--) {
tree[i] = tree[i*2] + tree[i*2+1];
tree2[i] = tree2[i*2] + tree2[i*2+1];
size[i] = size[i*2] + size[i*2+1];
}
}
void push(int node) {
if (lazy[node]) {
tree[node] += lazy[node] * size[node];
if (node < N) {
lazy[node*2] += lazy[node];
lazy[node*2+1] += lazy[node];
}
lazy[node] = 0;
}
}
void update(int node, int nl, int nr, int ql, int qr, int v) {
push(node);
if (ql > nr || qr < nl) return;
if (ql <= nl && nr <= qr) {
lazy[node] += v;
push(node);
return;
}
int mid = (nl+nr)/2;
update(node*2, nl, mid, ql, qr, v);
update(node*2+1, mid+1, nr, ql, qr, v);
tree[node] = tree[node*2] + tree[node*2+1];
}
void update2(int pos) {
auto upd = [&](int i) {
vector<int> ok;
for (int j = i+N; j; j >>= 1) {
ok.emplace_back(j);
}
for (int k = sz(ok)-1; k >= 0; k--) {
int j = ok[k];
push(j);
}
};
for (int i = pos; i <= pos+1; i++) {
if (i-1 >= 0 && i <= n) {
upd(i-1), upd(i);
tree2[i+N] = cost(tree[i-1+N], tree[i+N]);
for (int j = (i+N) >> 1; j; j >>= 1) {
tree2[j] = tree2[j*2] + tree2[j*2+1];
}
}
}
}
};
void test_case() {
int n, q, S, T;
cin >> n >> q >> S >> T;
vector<int> a(n+1);
for (int &x : a) cin >> x;
seg st(S, T, a);
while (q--) {
int l, r, x;
cin >> l >> r >> x;
st.update(1, 0, st.N-1, l, r, x);
st.update2(l);
st.update2(r);
cout << st.tree2[1] << '\n';
}
}
int main() {
cin.tie(0)->sync_with_stdio(0);
int t = 1;
// cin >> t;
while (t--) test_case();
}
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